Question

所以首先这是我应该要做的任务 “第二个编码挑战将是使用while循环来解决这两个条件

给出任何称为极限的数字，我们将找到并打印等于或低于极限的所有平方，因此：

给出30，您的第一个解决方案将打印1，4，9，16，25

第二种解决方案将最多打印多维数据集，因此：

给出30，您的第二个解决方案将打印1，8，2“

reply = True
while reply == True:
    limit = input("Choose any number ")
    if limit.isnumeric():
        limit = float(limit)
        reply = False
    else:
        print("What you have entered is not a number")
        reply = True

number = 1
square = list()
cube = list()
while number > 0:
    squarenumber = number ** 2
    if squarenumber > limit:
        break
    square.append(squarenumber)
    cubenumber = number ** 3
    if cubenumber > limit:
        break
    cube.append(cubenumber)
    number = number+1

print("All the squares below or equal to",limit,"are",*square)
print("All the cubes below or equal to", limit,"are",*cube)

这是我编写的代码，当我输入30作为“ limit”的值时，它会显示

All the squares below or equal to 30.0 are 1 4 9 16
All the cubes below or equal to 30.0 are 1 8 27

所以我不确定我做错了什么

Answer 1

当number的值变为4时会发生问题。在这种情况下，将计算平方并且条件14 > 30为假（30为limit）。但是随后您继续计算多维数据集，在这种情况下，条件64 > 30为真，因此循环中断。因此，一种方法是仅当值的平方大于限制时才中断循环。或者，您也可以反转条件（如果小于限制，则仅将正方形和立方体追加到列表中）

reply = True while reply == True: limit = input("Choose any number ") if limit.isnumeric(): limit = float(limit) reply = False else: print("What you have entered is not a number") reply = True number = 1 square = list() cube = list() while number > 0: squarenumber = number ** 2 # only append the square if it is less than limit value if squarenumber < limit: square.append(squarenumber) else: break # if the square value is greater than limit, then stop the loop cubenumber = number ** 3 # only append the cube if it is less than limit value if cubenumber < limit: cube.append(cubenumber) number = number+1 print("All the squares below or equal to",limit,"are",*square) print("All the cubes below or equal to", limit,"are",*cube)

Answer 2

检查squarenumber和cubenumber的限制无效，因为立方体的增长速度快于正方形。更好的解决方案是检查下一个正方形并收集多维数据集。

这是一个可能的解决方案

limit = 30
number = 1
square = list()
cube = list()
while number > 0:
    squarenumber = number ** 2
    square.append(squarenumber)
    if (number+1) ** 2 > limit:
        break
    cubenumber = number ** 3
    if cubenumber < limit:
        cube.append(cubenumber)

    number = number+1

print('square: {}'.format(square)) #square: [1, 4, 9, 16, 25]
print('cube: {}'.format(cube)) #cube: [1, 8, 27]

Python3：如何获得等于或低于数字的所有正方形和立方体

2 个答案: