Question

我试图在标头上接受以下请求：application / json 内容类型：application / json

{
  "userVO": {
     "userId": "899",
    "lstAuthToken":" uYCpPz6LTYVAZBee8S2cy5ZwFk%3D"
    }
}

发送到以下URL：http://54.84.41.76/wkconnects/rest/manageLST/validateLSTAuthToken进行验证。我将得到以下答复：

{
  "ccVerified": "true",
  "sessionAuthenticationToken": "KAA93bndyYaVPCVa8Sx%2FqLomPUP0CSBVHLRBQKMy3e9N%2FnYBEdjXHoN0lmxLfRwljH3PpkeOLIYS%0AQ4WVhF14015bz22HOAq%2B%2FBzMfzI3Z3jFmcuPDhZ6UGGv691Q1azHuQq8U7Biz8DSkPZV0qznohjD%0A43AhVR03LLFcffHI3do%3D",
  "status": "true"
}

我需要获取响应ccVerifiedand sessionAuthenticationToken作为变量，以便我可以说= true或= false等。

我尝试使用以下方法收效甚微：

<?php
$client = new GuzzleHttp\Client();
$res = $client->get('http://54.84.41.76/wkconnects/rest/manageLST/generateLSTAuthToken', [
    'auth' =>  ['899', 'uYCpPz6LTYVAZBeH9Xfi%2F2cy5ZwFk%3D']
]);
echo $res->getStatusCode();           // 200
echo $res->getHeader('content-type'); // 'application/json; charset=utf8'
echo $res->getBody();                 // {"type":"User"...'
var_export($res->json());     
?>

Answer 1

对不起，我大部分时间都是在卷曲的情况下做

.exe

JSON REST请求，PHP响应为变量

1 个答案: