Question

this image shows how every input results in execution in triangleCalc() function block我是Python的新手，在练习过程中我制作了此程序，它要求用户从圆形和三角形中选择两种形状之一。但是，每当我输入一个输入时，无论它是“ c”，“ t”，“ r”还是其他任何东西，都会执行计算三角形面积的函数。

'''
This is a Calculator program
which asks the user to select a shape
and then calculate its area based on given dimensions
'''
print ('Shape Area Calculator is now running')

def triangleCalc():
    base = float(input('Enter Base of triangle: '))
    height = float(input('Enter Height of triangle: '))
    areaT = 0.5 * base * height
    print ('The area of triangle is: ' + str(areaT))

def circleCalc():
     radius = float(input('Enter radius of Circle: '))
     areaC = 3.14159 * radius * radius
     print ('The area of Circle is ' + str(areaC))



print('Which shape would you like to calculate the Area of?')
print('Enter C for Circle or T for Triangle')
option = input()
if option == 't' or 'T':
    triangleCalc()
elif option == 'c'or 'C':
    circleCalc()
else:
    print ('Invalid Choice')

Answer 1

对于初学者来说，这似乎是多余的，但是if option == 't' or 'T'实际上应该写为if option == 't' or option == 'T'。

在旁注中，字符串（如'T'）在python中的值为True。因此，option == 't' or 'T'始终为True，而不考虑option == 't'的计算结果。

Answer 2

@ bstrauch24解释了我要添加的错误所在

如果您必须使用各种组合或输入，则每次比较都不好，那么请in运算符

option = input()
if option in ['t','T']:
    triangleCalc()
elif option in ['c','C']:
    circleCalc()

如何从用户那里获取输入并根据输入调用函数？

2 个答案: