我正在尝试绘制两个y轴的图,它们都是对数的。 Y1是左侧的y轴,Y2是右侧的y轴。此处,Y1的值是通过将Y2的值除以要在代码段中定义的 some_number 来计算的。由于为Y2轴选择了十进制数字,因此该数字看起来不正确:
import numpy as np
from numpy import *
import matplotlib as mpl
import matplotlib.pyplot as plt
from matplotlib import rcParams, cm
from matplotlib.ticker import MaxNLocator
#Plotting Decorations
xtick_label_size, ytick_label_size, axes_label_size, font_size, tick_width, lw, alpha = 18, 18, 20, 30, 2, 0.5, 0.5
plt.rcParams['mathtext.fontset'] = 'stix'
plt.rcParams['font.family'] = 'STIXGeneral'
mpl.rcParams['xtick.labelsize'], mpl.rcParams['ytick.labelsize'], mpl.rcParams['axes.labelsize'] = xtick_label_size, ytick_label_size, axes_label_size
some_number = mean(array([0.01614, 0.01381, 0.02411, 0.007436, 0.03223]))
f, (ax) = plt.subplots(1, 1, figsize=(10,100))
ax.set_xlim([1e8, 3e12])
ax.set_ylim([3e-1, 3e3])
ax.yaxis.set_major_locator(MaxNLocator(prune='upper'))
ax.set_ylabel('Y1', fontsize=12)
ax.set_xlabel('X', fontsize=12)
ax.set_xscale("log", nonposx='clip')
ax.set_yscale("log", nonposy='clip')
ax.xaxis.set_tick_params(width=tick_width)
ax.yaxis.set_tick_params(width=tick_width)
ax.get_xaxis().tick_bottom()
ax.get_yaxis().tick_left()
number = np.array([1e-4,1e-3,1e-2,1e-1,1,1e1,1e2,1e3])
numberticks = [i*some_number for i in number]
axsecond = ax.twinx()
axsecond.set_ylabel('Y2', fontsize=12)
axsecond.set_yscale("log", nonposy='clip')
axsecond.yaxis.set_tick_params(width=tick_width)
axsecond.set_yticks(number)
axsecond.set_yticklabels(['{:g}'.format(i) for i in numberticks])
f.subplots_adjust(top=0.98,bottom=0.14,left=0.14,right=0.98)
plt.setp([a.get_xticklabels() for a in f.axes[:-1]], visible=True)
f.tight_layout()
plt.show()
在获得有关为Y2定义正确标签的帮助之后,我想将这些标签表示为10的幂,类似于Y1。你知道怎么做吗?
答案 0 :(得分:1)
该想法是使轴限制同步。即如果第一个轴的y限制为[a,b]
,则第二个轴的y限制将为[a*factor, b*factor]
。
import matplotlib.pyplot as plt
import numpy as np
factor = 0.5
fig, ax = plt.subplots()
ax2 = ax.twinx()
ax.set_ylim([.1, 1e3])
ax2.set_ylim(np.array(ax.get_ylim())*factor)
ax.set_yscale("log")
ax2.set_yscale("log")
ax.plot([0,1],[1,100])
ax2.plot([0,1],np.array([1,100])*factor)
plt.show()