我正在使用Spring Data JPA和JPQL查询。尝试执行以下更新查询时，出现以下错误。我们如何解决这个问题？
查询：
@Query("UPDATE EmployeeSrc e SET e.employeeStat.employeeStatStatCd =?1, e.UpdtDt =?2, e.UpdtUserId =?3 "
+ "WHERE e.employeeStat.employeeStatStatCd =?4 AND e.EmpployeeNam =?5")
public void updateXXXXXXXXX(Long employeeStatStatCd, Date UpdtDt, String lstUpdtUserId,
Long employeeStatStatCd, String employeeName);
错误：
Caused by: Exception [EclipseLink-0] (Eclipse Persistence Services - 2.6.2.v20151217-774c696): org.eclipse.persistence.exceptions.JPQLException
Exception Description: Problem compiling [UPDATE EmployeeSrc e SET e.EmployeeStat.EmployeeStatCd =?1, e.UpdtDt =?2, e.UpdtUserId =?3 WHERE e.EmployeeStat.EmployeeStatCd =?4 AND e.EmployeeName =?5].
[20, 49] An association field cannot be used in an update item's path expression.
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.buildException(HermesParser.java:155)
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.validate(HermesParser.java:347)
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.populateQueryImp(HermesParser.java:278)
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.buildQuery(HermesParser.java:163)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.buildEJBQLDatabaseQuery(EJBQueryImpl.java:142)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.buildEJBQLDatabaseQuery(EJBQueryImpl.java:116)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.<init>(EJBQueryImpl.java:102)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.<init>(EJBQueryImpl.java:86)
at org.eclipse.persistence.internal.jpa.EntityManagerImpl.createQuery(EntityManagerImpl.java:1614)
... 61 more