Question

我正尝试从每40公斤中减去2公斤的重量。如果我有200Kg，则扣除额将为10kg，依此类推...问题是我每40kg使用IF，请参见编码。请帮助我尽可能地简化此代码。

  public void onClick(View view) {
            String s = edW.getText().toString();
            Float w= Float.parseFloat(s);
            Float weight = w*40;
            if (weight <= 20){
                Float oneKG = weight - 1;
                txtV.setText("Total KGs: "+ oneKG);
            }
             if (weight>20 && weight <=40){
                Float twoKG = weight - 2;
                txtV.setText("Total KGs: "+ twoKG);
            }

            if (weight>40 && weight <=80){
                Float fourKG = weight - 4;
                txtV.setText("Total KGs: "+ fourKG);
            }
             if (weight>80 && weight <=120){
                Float sixKG = weight - 6;
                txtV.setText("Total KGs: "+ sixKG);
            }
             if (weight>120 && weight <=160){
                Float eightKG = weight - 8;
                txtV.setText("Total KGs: "+ eightKG);
            }
             if (weight>160 && weight <=200){
                Float tenKG = weight - 10;
                txtV.setText("Total KGs: "+ tenKG);
            }
            else {
                txtV.setText("Else Running");
            }


        }

screenshot

Answer 1

尝试以下代码，应该可以解决您的问题

class Value{
    public int wholeNumber;
    public int decimalNumber;
}

private Value getWholeDecimalNumber(String s) {
    String[] arr = String.valueOf(s).split("\\.");
    Value value = new Value();
    value.wholeNumber = Integer.parseInt(arr[0]);
    if (arr.length > 1) {
        value.decimalNumber = Integer.parseInt(arr[1]);
    }
    return value;
}

public void onClick(View view) {
    String s = edW.getText().toString();
    Value value = getWholeDecimalNumber(s);
    int w= value.wholeNumber;
    int weight = w*40 + value.decimalNumber;
    int weightToDeduct = w*2;

    if (value.decimalNumber > 0) {
        if (value.decimalNumber > 20) {
            weightToDeduct += 2;
        }
        else {
            weightToDeduct += 1;
        }
   }
   txtV.setText("Total KGs: "+ (weight - weightToDeduct));

}

例如- a）对于1作为输入，重量= 1x40 = 40，weightToDeduct = 1x2 = 2，总千克=（重量-weightToDeduct）= 40-2 = 38kg

b）输入5时，重量= 5x40 = 200，weightToDeduct = 5x2 = 10，总计kg =（重量-weightToDeduct）= 200-10 = 190kg

Answer 2

您还可以尝试将权重除以20：）

Answer 3

除以40：

$$prods

注意：当答案的权重完全等于40的倍数时，此答案的较早版本出现一个错误的错误。

如果您真的不希望它超过200，则可以在计算public void onClick(View view) { String s = edW.getText().toString(); float weight = 40 * Float.parseFloat(s); if (weight <= 20) { txtV.setText("Total KGs: " + (weight - 1)); } else { int forties = (int) Math.ceil(weight / 40f); txtV.setText("Total KGs: " + (weight - (forties * 2))); } }之后但在完成其余工作之前将其添加：

float weight

它提供了与原始内容相同的语义。

减重可以简化代码

3 个答案: