Question

c1=["q","q","q","q","q","q"]
c2=["x","x","x","x","x","x"]
c3=["w","w","w","w","w","w"]
ca=["c","e","a","d"]
cb=["y","z","s","f"]
cc=["y","z","s","f"]
df1=pd.DataFrame(c1, columns=['c1'])
df2=pd.DataFrame(c2, columns=['c2'])
df3=pd.DataFrame(c3, columns=['c3'])
df4=pd.DataFrame(ca, columns=['ca'])
df5=pd.DataFrame(cb, columns=['cb'])
df6=pd.DataFrame(cc, columns=['cc'])
df7=pd.concat([df1,df2,df3,df4,df5,df6],axis=1)
df7

我想要做的是连接列表（不同长度）并创建数据框。我无法使用zip（）来实现它。有什么简单的方法吗？

Answer 1

您可以向concat提供系列列表而不是数据帧列表。字典对于可变数量的变量是个好主意，它允许您将将来的列名称存储为键。

d = {'c1': c1, 'c2': c2, 'c3': c3, 'ca': ca, 'cb': cb, 'cc': cc}

df = pd.concat([pd.Series(v, name=k) for k, v in d.items()], axis=1)

print(df)

  c1 c2 c3   ca   cb   cc
0  q  x  w    c    y    y
1  q  x  w    e    z    z
2  q  x  w    a    s    s
3  q  x  w    d    f    f
4  q  x  w  NaN  NaN  NaN
5  q  x  w  NaN  NaN  NaN

如何将列表连接到Pandas中的数据框

1 个答案: