Question

我正在为类AccountMessage创建一个组合密钥，该组合密钥是accountId和messageId。我的代码如下

@Embeddable
public class AccountMessagePK implements Cloneable, Serializable {

    /** Serial Version UID. */
    private static final long serialVersionUID = -1L;

    @ManyToOne( cascade = { CascadeType.PERSIST, CascadeType.MERGE }, fetch = FetchType.LAZY )
    @org.hibernate.annotations.Cascade({org.hibernate.annotations.CascadeType.SAVE_UPDATE})
    @Basic( optional = false )
    @JoinColumn(name = "accountId", nullable = false , insertable = false, updatable = false )
    private Account account;

    @ManyToOne( cascade = { CascadeType.PERSIST, CascadeType.MERGE }, fetch = FetchType.LAZY )
    @org.hibernate.annotations.Cascade({org.hibernate.annotations.CascadeType.SAVE_UPDATE})
    @Basic( optional = false )
    @JoinColumn(name = "messageId", nullable = false , insertable = false, updatable = false )
    private Message message;

    @Basic( optional = false )
    @Column( name = "accountId", nullable = false  )
    public Account getAccount() {
        return this.account;

    }

    public void setAccount(final Account account) {
        this.account = account;
    }

    @Basic( optional = false )
    @Column( name = "messageId", nullable = false  )
    public Message getMessage() {
        return this.message;

    }
    public void setMessage(final Message message) {
        this.message = message;
    }

}

帐户实体就像

@Entity
@Table(name = "Account")
public class Account implements Cloneable, Serializable {

    /** Serial Version UID. */
    private static final long serialVersionUID = -1L;

    private Integer id = 0;
    private String externalId;

    .....


    public Account() {

    } 

    public Account(Integer id) {
        this.id = id;
    }

    public Account(Integer id, String externalId, Boolean isDeleted) {

        this.id = id;
        this.externalId = externalId;
        this.isDeleted = isDeleted;
    }



@Basic( optional = true )
    @Column( name = "externalId", length = 40  )
    public String getExternalId() {
        return this.externalId;

    }


    public void setExternalId(final String externalId) {
        this.externalId = externalId;
    }

@Id 
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Basic( optional = false )
    @Column( name = "accountId", nullable = false  )
    public Integer getId() {
        return this.id;

    }

    public void setId(final Integer id) {

        this.id = id;
    }

......

}

但是，当我尝试使用Hibernate条件按如下所述获取AccountMessage时，

Criteria crit = sess.createCriteria(AccountMessage.class);
crit.add(Restrictions.eq("id.account.externalId", filterValue));
crit.list();

我遇到错误

org.hibernate.QueryException: could not resolve property: id.account.externalId of: package.path.AccountMessage

我在网上搜索了Google，发现有人遇到相同的错误，但该解决方案似乎不适用于我的案子。任何想法？预先感谢。

无法解析组合键中属性的：的属性

0 个答案: