将用户输入传递到GQL查询中

时间:2018-07-27 19:12:00

标签: mongodb mongoose graphql react-apollo

我目前正在尝试找出如何通过将用户通过表单提交的文本数据用作返回结果数组的查询中的变量参数来实现搜索功能的方法。 AssetQueryInit查询的结果很好。 (AssetQueryInit只是呈现硬编码查询的结果)

我是新手,我们将不胜感激!

GraphQL服务器

const typeDefs = `
  type Asset {
    _id: ID
    assetName: String
    headline: String
    language: String
    sentimentNegative: Float
    sentimentNeutral: Float
    sentimentPositive: Float
    firstCreated: String


  }
  type Query {
    asset(assetName: String!): Asset
    assetAll(assetName: String!): [Asset]
  }
`;

const resolvers = {
  Query: {
    asset: (_,{assetName})=> Asset.findOne({assetName : assetName }),
    assetAll: (_,{assetName}) => Asset.find({assetName: assetName})
  }
};

const server = new GraphQLServer({ typeDefs, resolvers });

反应

const AssetAllQuery = gql`
{
    assetAll(assetName: $text){
      _id
      assetName
      headline
      firstCreated
      sentimentNegative
      sentimentPositive
      sentimentNeutral
    }
} 
`;



class App extends Component {
  assetAll = async (text) =>{
    await this.props.assetAll({
      variables:{
        assetName: text
      },
      update:(store,{data: {assetAll}}) => {
        const data = store.readQuery({query: AssetAllQuery});
        data.assetAll.unshift(assetAll);
      }
    });
  };

  render() {
        const {
            data : { loading, assetAll }
          } = this.props;
        console.log("test");
    if(loading){
      return null;
    }
    return (
      <div className="App">
      <Form submit ={this.getAllAssets}/>
      {assetAll.map(Asset => <div key={Asset._id}>{Asset.headline} | {Asset.sentimentNeutral > Asset.sentimentPositive ?  (Asset.sentimentNeutral > Asset.sentimentNegative ? "Neutral" : "Sell") : "Buy"} </div>)}
      </div>
    );
  }
};

export default compose(
  graphql(AssetAllQuery, {name: "assetAll"}),
  graphql(AssetQueryInit)
  )(App);

输出

[GraphQL error]: Message: Variable "$text" is not defined., Location: [object Object],[object Object], Path: undefined  bundle.js:837:32

[Network error]: Error: Response not successful: Received status code 400

1 个答案:

答案 0 :(得分:1)

在查询中,基本上必须将您使用的任何$variables都声明为整个事物的输入参数:

const AssetAllQuery = gql`
AssetAll($assetName: String!) {
    assetAll(assetName: $assetName){
        ...
    }
} 
`;

顶级操作名称并不重要; $variable有自己的声明类型,必须与查询主体中使用的类型匹配;并且在进行查询时,variables:的名称必须与声明的查询参数的名称匹配。