Question

如果我有这张桌子：

UserID | Score1 | Score2
1      | 10     | 5
2      | 50     | 15
3      | 30     | 25
1      | 50     | 10
2      | 0      | 100
3      | 1      | 5

我想将此表排序为得分1 +得分2，但我也希望得到单独的分数。

但必须按userId分组，并且只返回用户的最高分（因此MAX得分1 +得分2）。

但我不能做一个小组，因为那时我将排除具有相同分数的用户。这对我来说是一个决战者......

从上表中，结果应为：

UserID | Score1 | Score2 | TotalScore
2      | 0      | 100    | 100
1      | 50     | 10     | 60
3      | 30     | 25     | 55

Answer 1

SELECT UserID, Score1, Score2, Score1 + Score2 AS "Total"
FROM myTable
ORDER BY Score1 + Score2 DESC

你不需要GROUP BY，因为它不是一个聚合函数，它只是一个计算列。

修改

您需要在分组后加上最高总分和用户ID。这是一个带有公用表表达式的示例：

WITH maxScores AS (
    SELECT UserID AS "id", MAX(Score1 + Score2) AS "total"
    FROM scores 
    GROUP BY UserID
)
SELECT s.UserID, s.Score1, s.Score2, s.Score1 + s.Score2 AS "Total"
FROM scores s
JOIN maxScores m ON s.UserID = m.id
    AND s.Score1 + s.Score2 = m.Total

Answer 2

select UserID, Score1, Score2
    from YourTable
    order by Score1 + Score2

Answer 3

你看起来像这样吗？

declare @t table( id int, s1 int, s2 int)

insert into @t (id, s1, s2) values (0, 10, 5)
insert into @t (id, s1, s2) values (1, 50, 15)
insert into @t (id, s1, s2) values (2, 20, 25)
insert into @t (id, s1, s2) values (1, 30, 0)

select id, s1, s2, (s1+s2) as 'total' from @t order by (s1+s2) desc, id asc

1   50  15  65
2   20  25  45
1   30  0   30
0   10  5   15

Answer 4

那么，这就是你想要的吗？

declare @t table( id int, s1 int, s2 int)

insert into @t (id, s1, s2) values (0, 10, 5)
insert into @t (id, s1, s2) values (1, 50, 15)
insert into @t (id, s1, s2) values (2, 30, 25)
insert into @t (id, s1, s2) values (1, 40, 0)

select id, MAX(s1) max_s1, MAX(s2) max_s2, SUM(total) total from
(select id, s1, s2, (s1+s2) as 'total' from @t) a
group by id
order by total

我担心您在使用相同的s1对行进行分组后，确实没有说明您要对s2和id做什么...

Answer 5

这个怎么样？

SELECT Q1.UserID, Q1.Score1, Q1.Score2, Q1.Total
FROM (SELECT UserID, Score1, Score2, (Score1+Score2) AS Total
    FROM myTable) AS Q1,
(SELECT UserId, Max(Score1 + Score2) As Total FROM myTable GROUP BY UserId) As Q2
WHERE Q1.UserId=Q2.UserId AND Q1.Total=Q2.Total
ORDER BY 4 DESC, 1

Answer 6

这回答了吗？假设你想要为同一个id包含相同score1 + score2的重复项（如果没有将DENSE_RANK更改为ROW_NUMBER）

create table #data (id int,score1 int, score2 int)
insert into #data Values (0,10,5)
insert into #data Values (1,50,15)
insert into #data Values (2,30,25)
insert into #data Values (1,40,0)

** edit for sorting as per question revision**
;with scores AS
(
SELECT
id
,score1
,score2
,DENSE_RANK() OVER (PARTITION BY id ORDER BY score1 + score2 DESC) AS score_rank
FROM #data
)
SELECT 
id
,score1
,score2
,score1 + score2 AS sum_
FROM scores where score_rank = 1
ORDER BY score1 + score2 DESC

按结果分组

6 个答案:

修改