Question

我正在尝试使用PowerMockito模拟私有方法。

示例代码如下。

理想情况下， m2（）应该返回“来自间谍方法”。

不确定会丢失什么。

请澄清。

Sample.java

import java.io.IOException;

public class Sample {

    public void m1(String input) throws IOException {
        System.out.println("Sample.m1() BEGIN");
        String r = m2(input);
        System.out.println("Sample.m1() END--> " + r);
    }

    private String m2(String s) {
        System.out.println("Sample.m2()" + s);
        return "From m2 method";
    }

}

SampleTest.java

import static org.mockito.Matchers.anyString;

import org.junit.Test;
import org.junit.runner.RunWith;
import org.powermock.api.mockito.PowerMockito;
import org.powermock.core.classloader.annotations.PrepareForTest;
import org.powermock.modules.junit4.PowerMockRunner;

@RunWith(PowerMockRunner.class)
@PrepareForTest({ Sample.class })
public class SampleTest {

    @Test
    public void testM1() throws Exception {
        Sample spy = PowerMockito.spy(new Sample());
        PowerMockito.doReturn("from spy method").when(spy, "m2", anyString());

        Sample sample = new Sample();
        sample.m1("Hi m1!!!");
    }
}

输出

Sample.m1() BEGIN
Sample.m2()Hi m1!!!
Sample.m1() END--> From m2 method

Answer 1

我需要在间谍实例而不是示例实例上调用m1（）。感谢Giacomo Alzetta的建议。

修改后的代码：

@Test
    public void testM1() throws Exception {
        Sample spy = PowerMockito.spy(new Sample());
        PowerMockito.doReturn("from spy method").when(spy, "m2", anyString());

        spy.m1("Hi m1!!!");
    }

使用PowerMockito模拟私有方法

1 个答案: