覆盆子上的Kivy:游标在窗口外面

时间:2018-07-27 12:32:57

标签: python kivy raspberry-pi3

我正在使用Python3和Kivy 1.11.0dev在RaspberryPi 3上开发GUI。 GUI正在工作,启动后以全屏模式运行(据我所知,自Kivy 1.9.x起,无法将Kivy应用程序作为窗口运行)并且可见鼠标光标。现在唯一的问题是,如果用户向左,向右,向上或向下移动得太远,都可以将鼠标移出可见区域。如果发生这种情况,很难使光标返回到可见区域。

我做了很多尝试来防止这种情况,或者使光标自动返回窗口,但是没有成功。在类似的帖子中,我尝试了如下操作:

Window.bind(on_cursor_leave=self.on_leave)

def on_leave(self, *args):
    if self.hold:
    print('Cursor leaved Window')
    # call api calls here

我也试图抓住鼠标

Window.bind(grab_mouse=self.on_leave)

有人能在离开后将光标放回可见区域或设置不能离开的边界吗?

编辑:也许此输出有帮助:

[INFO   ] [Logger      ] Record log in /home/pi/.kivy/logs/kivy_18-07-30_8.txt
[INFO   ] [Image       ] Providers: img_tex, img_dds, img_sdl2, img_pil, img_gif (img_ffpyplayer ignored)
[INFO   ] [Kivy        ] v1.11.0.dev0, git-0471549, 20180720
[INFO   ] [Python      ] v3.4.2 (default, Oct 19 2014, 13:31:11) 
[GCC 4.9.1]
[INFO   ] [KivyMD      ] KivyMD version: 0.1.2
[INFO   ] [Factory     ] 194 symbols loaded
[INFO   ] [Text        ] Provider: sdl2
[INFO   ] [Window      ] Provider: egl_rpi
[INFO   ] [GL          ] Using the "OpenGL ES 2" graphics system
[INFO   ] [GL          ] Backend used <gl>
[INFO   ] [GL          ] OpenGL version <b'OpenGL ES 2.0'>
[INFO   ] [GL          ] OpenGL vendor <b'Broadcom'>
[INFO   ] [GL          ] OpenGL renderer <b'VideoCore IV HW'>
[INFO   ] [GL          ] OpenGL parsed version: 2, 0
[INFO   ] [GL          ] Shading version <b'OpenGL ES GLSL ES 1.00'>
[INFO   ] [GL          ] Texture max size <2048>
[INFO   ] [GL          ] Texture max units <8>
[INFO   ] [Window      ] virtual keyboard not allowed, single mode, not docked
[INFO   ] [GL          ] NPOT texture support is available
xclip version 0.12
Copyright (C) 2001-2008 Kim Saunders et al.
Distributed under the terms of the GNU GPL
[INFO   ] [Clipboard   ] Provider: xclip
[INFO   ] [CutBuffer   ] cut buffer support enabled
[INFO   ] [ProbeSysfs  ] device match: /dev/input/event0
[INFO   ] [HIDInput    ] Read event from </dev/input/event0>
[INFO   ] [ProbeSysfs  ] device match: /dev/input/event1
[INFO   ] [HIDInput    ] Read event from </dev/input/event1>
[INFO   ] [Base        ] Start application main loop
[INFO   ] [HIDMotionEvent] using <b'MLK USB Composite Device\x00                                                                                                                                                                                                                                       '>
[INFO   ] [HIDMotionEvent] using <b'MLK USB Composite Device\x00  

3 个答案:

答案 0 :(得分:2)

解决方案

  1. 在构造函数__init__()中,将on_cursor_leave事件绑定到回调方法,例如cursor_leave()
  2. Window.grab_mouse()方法内使用cursor_leave()。有关详细信息,请参阅示例。

摘要

class GrabMouseDemo(Label):

    def __init__(self, **kwargs):
        super(GrabMouseDemo, self).__init__(**kwargs)
        Window.bind(mouse_pos=self.mouse_pos)
        Window.bind(on_cursor_leave=self.cursor_leave)

Window » grab_mouse()

grab_mouse()
     

鼠标-不会离开窗口

     

注意

     

此功能需要SDL2窗口提供程序。

示例

from kivy.app import App
from kivy.uix.label import Label
from kivy.core.window import Window


class GrabMouseDemo(Label):

    def __init__(self, **kwargs):
        super(GrabMouseDemo, self).__init__(**kwargs)
        Window.bind(mouse_pos=self.mouse_pos)
        Window.bind(on_cursor_leave=self.cursor_leave)

    def mouse_pos(self, window, pos):
        self.text = str(pos)

    def cursor_leave(self, window):
        print("cursor_leave:")
        Window.grab_mouse()


class TestApp(App):
    title = "Kivy Grab Mouse Demo"

    def build(self):
        return GrabMouseDemo()


if __name__ == "__main__":
    TestApp().run()

输出

Img01

答案 1 :(得分:1)

好的,我解决了问题。这不是我最喜欢的解决方案,但可以运行:

# Set mouse back to visible window when leaving 1920x1080
def mouse_pos(self, window, pos):
    try:
        #pos_width = int(pos[0])
        #pos_height = int(pos[1])

        if int(pos[0]) <= 0:                # Mouse outside, LEFT
            window.mouse_pos = (5, int(pos[1]))
        if int(pos[0]) > self.win_width:    # Mouse outside, RIGHT
            window.mouse_pos = (1900, int(pos[1]))
        if int(pos[1]) < 0:                 # Mouse outside, BOTTOM
            window.mouse_pos = (int(pos[0]), 20)
        if int(pos[1]) > self.win_height:   # Mouse outside, TOP
            window.mouse_pos = (int(pos[0]), 1060)

光标离开窗口后将向后移动。

答案 2 :(得分:0)

这时我的方法是:

class WSRMEGUI(BoxLayout):
    ...

    def __init__(self, **kwargs):
        super(WSRMEGUI, self).__init__(**kwargs)
        Window.bind(mouse_pos=self.mouse_pos)

    def mouse_pos(self, window, pos):
        poswidth = int(pos[0])
        posheight = int(pos[1])
        winwidth = int(window.width)
        winheight = int(window.height)


        if poswidth <= 0:
            Window.grab_mouse()
        if poswidth > winwidth:
            Window.grab_mouse()
        if posheight < 0:
            Window.grab_mouse()
        if posheight > winheight:
            Window.grab_mouse()

所以,如果光标离开窗口

Window.grab_mouse()

每次都被调用,但没有任何效果...当光标离开允许区域时,是否可以将光标设置回窗口?