Question

我已经定义了一个方法，并尝试在构造函数内调用它，但是，即使在构造函数上方定义了“ userDetailsValidation”，也遇到了未定义错误。这是我的代码：

class PythonAssignment:
    FirstName = ""
    LastName = ""
    dateOfBirth = ""

    def userDetailsValidation(fieldvalue, fieldName, database):
        for entry in database:
            if fieldName in entry and entry[fieldName] == fieldvalue:
                return True

    def printRequiredUserInfo(FirstName, fieldname, AccountNumber, Accountbalance, Database):
        for entry in Database:
            if fieldname in entry and entry[fieldname] == FirstName:
                print(entry)

    def __init__(self):
        self.FirstName = str(input("Enter First Name").upper())
        while True:
            if (userDetailsValidation(FirstName, "FirstName", newSortedDatabase)) == True:
                userDetails.append(FirstName)
                break
            else:
                print(" First Name did not matched with the database")
                FirstName = str(input("Enter First Name").upper())


userObject = PythonAssignment()

Answer 1

您应该将不使用self的方法标记为静态

@staticmethod
def userDetailsValidation(fieldvalue, fieldName, database):

和

@staticmethod
def printRequiredUserInfo(FirstName,fieldname,AccountNumber,Accountbalance,Database):

然后调用它们，使用类范围

if PythonAssignment.userDetailsValidation(FirstName, "FirstName", newSortedDatabase):

如果您的方法确实需要对象的状态，则应从self

调用它们

self.SomeMethod(args, etc)

即使上面在python中定义了方法名也未定义错误

1 个答案: