Question

我是python的新手。我想运行此代码，但是遇到语法错误，我不知道如何解决。我正在运行它

http://webvr.virtualskillslab.de/0.8.0

 names=['A','B','C']       
 cars=['mercedes','porshe','hyundai'] 
 numbers=[1,2,3]   
        for name in names:   
           file_name=names+".txt"
           text_file = open(file_name, "w")                   
           for car in cars:   
             print(cars)                    
             for number in numbers:   
              txt2write=name+" has "+str(number)+" "+car 
              print(name+" has "+str(number)+" "+car)
              text_file.write("%s \n" %(txt2write))


text_file.close()           
print("That's all.")

有什么主意吗？再说一遍，这是我的第一个代码..（就像我对Python完全陌生，对嵌套循环一无所知）

Answer 1

缩进不正确，第file_name = names + "txt"行也应使用name而不是names。这是完整的固定代码：

names=['A','B','C']       
cars=['mercedes','porshe','hyundai'] 
numbers=[1,2,3]   
for name in names:   
    file_name=name+".txt"
    text_file = open(file_name, "w")                   
    for car in cars:   
        print(cars)                    
        for number in numbers:   
            txt2write=name+" has "+str(number)+" "+car 
            print(name+" has "+str(number)+" "+car)
            text_file.write("%s \n" %(txt2write))
    text_file.close()     

print("That's all.")

Answer 2

names=['A','B','C']
cars=['mercedes','porshe','hyundai']
numbers=[1,2,3]
for name in names:
    file_name=name+".txt" # leave 4 spaces for the outermost level
    text_file = open(file_name, "w")
    for car in cars:
        print(cars) # leave 8 spaces for the innermost level
        for number in numbers:
            txt2write=name+" has "+str(number)+" "+car
            print(name+" has "+str(number)+" "+car)
            text_file.write("%s \n" %(txt2write))
    text_file.close()
print("That's all.")

获取正确的for循环缩进。

file_name=names+".txt"也应该是file_name=names+".txt"

供参考-https://www.python.org/dev/peps/pep-0008/

python，嵌套嵌套循环

2 个答案: