Question

我有2张桌子- “俱乐部会员”表包含3个字段，例如：

var firstString = "<h3>askhaks</h3><h3>1212</h3><h1 style='color:red;text-decoration:underline;'><a href=''><span id='123'><i class='fa fa-inr'></i></span> Hello! Admin</span></a></h1><p>This is the content of page 'String Replace in Javascript'</p><h1>First</h1><span><h1>Second</h1>Thank You for visiting this page</span><h1>Third</h1>";
const doc = new DOMParser().parseFromString(firstString, 'text/html');
const h1Text = doc.querySelector('h1').textContent.trim();
console.log(firstString.replace(h1Text, 'foo bar new string'));

“月份列表”表，其中包含1个字段：

"Member_ID",   "Date_Of_Birth"
         1         13/4/1980              
         2         20/4/1990
         3         30/12/1970
         4         20/11/1960

我希望生成一个查询，显示月份，Number_Of_Birthdays

例如：

   "Month"  
   4-2017
   5-2017
   ...
   11-2017

   12-2017
   ...
   4-2018
   ...
   11-2018
   12-2018

如何在访问中做到这一点？

谢谢

Answer 1

使用inner join和聚合函数count

在编辑问题时，请尝试以下查询，请记住此处的日期格式是主要问题，因此请保持相同的格式

select ML.Month,Number_Of_Birthdays_Of_Club_Memebers   from

    (
        select format(Member_Date_Of_Birth,"mm-yyyy") as  month_number,count(Member_ID) as Number_Of_Birthdays_Of_Club_Memebers  
        from club_members
        group by format(Member_Date_Of_Birth,"mm-yyyy")
    )as T1
    inner join months_list as ML
    T1.month_number=ML.Month

Answer 2

如果要按加入日期计算成员数，请使用此选项。

Select b.Month_Date, Count(a.*) as Total_Members
From Club_Members as a INNER Join Month_List as b 
ON a.Member_Join_Date=b.Month_Date
Group BY  B.month_Date

Answer 3

尝试一下：

SELECT Month_Date, sum(MemberCount) 
  FROM (
SELECT c.Member_ID, c.Member_Join_Date, m.Month_Date,CASE WHEN c.Member_Join_Date < m.Month_Date THEN 1 ELSE 0 END MemberCount 
  FROM club_members c, months_list m  
 ) s
GROUP BY Month_Date

按月访问查询数

3 个答案: