实习生ID是一个字母数字值。
问题是运行该程序后,搜索代码仅适用于数字。不适用于字母数字。我该怎么解决。
private void button1_Click(object sender, EventArgs e)
{
if (txtsearch.Text != "")
{
MessageBox.Show("Please type intern number");
}
else
{
try
{
con.Open();
string SelectQuery2 = "SELECT * FROM interndetails WHERE internnumber =" + Convert.ToString(txtsearch.Text);
cmd4 = new MySqlCommand(SelectQuery2, con);
mdr2 = cmd4.ExecuteReader();
if (mdr2.Read())
{
textBox11.Text = mdr2.GetString("name");
textBox9.Text = mdr2.GetString("idnumber");
textBox6.Text = mdr2.GetString("status");
textBox12.Text = mdr2.GetString("statusdate");
textBox13.Text = mdr2.GetString("intakedate");
textBox14.Text = mdr2.GetString("fplacementdate");
textBox10.Text = mdr2.GetString("secbrdpt");
textBox15.Text = mdr2.GetString("periodcomplertion");
mdr2.Close();
con.Close();
}
else
{
MessageBox.Show("No Interns were found!");
txtsearch.Clear();
txtsearch.Focus();
}
con.Close();
}
catch (MySqlException x)
{
MessageBox.Show(x.Message);
con.Close();
}
}
}
}
答案 0 :(得分:0)
类似的事情应该起作用:
string SelectQuery2 = "SELECT * FROM interndetails WHERE internnumber = @internNumber";
cmd4 = new MySqlCommand(SelectQuery2, con);
cmd4.Parameters.Add("@internNumber", MySqlDbType.String).Value = txtsearch.Text;
答案 1 :(得分:0)
可能对您有帮助
SELECT * FROM intern详细信息,其中concat(internnumber,'')='“ + Convert.ToString(txtsearch.Text)+”'“