是否有更优化的方法来获取以“,”结尾并以“。”结尾的子字符串。比这样?
if (paramsText != null)
{
while (paramsText.contains(","))
{
params.add(paramsText.substring(0, paramsText.indexOf(",")));
paramsText = paramsText.substring(
paramsText.indexOf(",") + 1, paramsText.length());
}
params.add(paramsText);
}
答案 0 :(得分:3)
因为你实际上没有检查“。”你可以这样做:
String[] params = paramsText.split(",");
答案 1 :(得分:2)
也许这样的事情适合你:
String str = "There is, a more optimal, way to obtain. subtrings which,"
+ "are separated by, and ended by. than this way.";
String[] substrings = str.split("\\s*[.,]\\s*");
for (String substr : substrings)
System.out.println("\"" + substr + "\"");
<强>输出:强>
"There is"
"a more optimal"
"way to obtain"
"subtrings which"
"are separated by"
"and ended by"
"than this way"