我正在尝试设置输出参数thirdPartyId的值,但我在missing or invalid option
语句中收到错误set thirdPartyId
。
PROCEDURE usp_insert_user( userType VARCHAR2,
logonId VARCHAR2,
title VARCHAR2,
firstName VARCHAR2,
middleName VARCHAR2,
lastName VARCHAR2,
comments VARCHAR2,
thirdPartyId OUT number) AS
begin
set thirdPartyId := select max(third_party_id) + 1 from third_party_user_temp;
insert into THIRD_PARTY_USER_TEMP
(Third_party_id,web_logon_id,prsn_type_cd,prsn_title_nm,
prsn_first_nm,prsn_mdl_nm,prsn_last_nm,addtnl_third_party_txt)
VALUES(thirdPartyId,logonId,upper(userType),title,
firstName,middleName,lastName,comments)
;
end usp_insert_user;
这样做的正确方法是什么?
谢谢!
更新:这样更安全吗?
insert into THIRD_PARTY_USER_TEMP
(Third_party_id,web_logon_id,prsn_type_cd,prsn_title_nm,
prsn_first_nm,prsn_mdl_nm,prsn_last_nm,addtnl_third_party_txt)
VALUES((select max(third_party_id) + 1 from third_party_user_temp),logonId,upper(userType),title,
firstName,middleName,lastName,comments)
returning third_party_id into thirdPartyId
答案 0 :(得分:3)
你可以这样做:
select max(third_party_id) + 1 into thirdPartyId from third_party_user_temp;
如果两个人可以同时运行此问题,则可能会遇到争用问题 - 两者都可能以相同的新thirdPartyId
结束。您可以查看序列以避免这种情况。
thirdPartyIdSeq
的序列,你可以这样做:
PROCEDURE usp_insert_user( userType VARCHAR2,
logonId VARCHAR2,
title VARCHAR2,
firstName VARCHAR2,
middleName VARCHAR2,
lastName VARCHAR2,
comments VARCHAR2,
thirdPartyId OUT number) AS
begin
insert into THIRD_PARTY_USER_TEMP
(Third_party_id,web_logon_id,prsn_type_cd,prsn_title_nm,
prsn_first_nm,prsn_mdl_nm,prsn_last_nm,addtnl_third_party_txt)
VALUES(third_party_id_seq.nextval,logonId,upper(userType),title,
firstName,middleName,lastName,comments)
returning third_party_id into thirdPartyId;
end usp_insert_user;
这使用序列生成下一个ID,returning
子句填充OUT参数。
您也可以使用序列来避免该过程并在触发器中执行ID生成。这种方法有很多例子,尤其是在这个网站上。
CREATE OR REPLACE TRIGGER third_party_user_temp_bi
BEFORE INSERT ON third_party_user_temp
FOR EACH ROW
BEGIN
SELECT thirdPartyIdSeq.NEXTVAL
INTO :new.third_party_id
FROM dual;
END;
/
您的插入不需要指定要使用的ID。