Question

我需要确定几天的时间来确定周末是否在此范围内。如果是这样，我将2天添加到最终范围（周一至周日，将其更改为周一至周三）。（基于用户选择的天数，例如5天）

我已经提出了一种解析日期的方法（不确定这是否是最佳实践）并且不确定如何继续。到目前为止：

////TODO Refactor to new class
DateTime startingDate = DateTime.Parse("07/25/2018");//TODO Insert variable from poted form 
DateTime endingDate = DateTime.Parse("07/08/2018");//TODO Insert variable from posted form

 var days=  Enumerable.Range(0, 1 + endingDate.Subtract(startingDate).Days)
                .Select(offset => startingDate.AddDays(offset))
                .ToList();

我认为，我需要像下面的伪代码一样进行操作：

if day.contains dayOfWeek.Saturday ||Or dayofWeek.Friday {Add.Days(2)}

但是我不知道该怎么做。

Answer 1

用户提供结束日期和工作日数，这将产生一个包含所需金额的列表

DateTime endingDate = DateTime.ParseExact("07/25/2018","MM/dd/yyyy", System.Globalization.CultureInfo.InvariantCulture);//TODO Insert variable from poted form 
int workingDays = 5;
List<DateTime> dates = new List<DateTime>();
DateTime startingDate = endingDate;
while(dates.Count<workingDays)
{
    if(startingDate.DayOfWeek != DayOfWeek.Sunday && startingDate.DayOfWeek != DayOfWeek.Saturday)
    {
        dates.Insert(0, startingDate);
    }
    startingDate = startingDate.AddDays(-1);
}

输出将为

20个工作日内：

01   2018-06-28   Thursday
02   2018-06-29   Friday
03   2018-07-02   Monday
04   2018-07-03   Tuesday
05   2018-07-04   Wednesday
06   2018-07-05   Thursday
07   2018-07-06   Friday
08   2018-07-09   Monday
09   2018-07-10   Tuesday
10   2018-07-11   Wednesday
11   2018-07-12   Thursday
12   2018-07-13   Friday
13   2018-07-16   Monday
14   2018-07-17   Tuesday
15   2018-07-18   Wednesday
16   2018-07-19   Thursday
17   2018-07-20   Friday
18   2018-07-23   Monday
19   2018-07-24   Tuesday
20   2018-07-25   Wednesday

Answer 2

首先计算整个周末。然后，将结果添加到开始日期。这是我的解决方案。希望对我有帮助！

static IEnumerable<DateTime> GetDaysBetween(DateTime start, DateTime end)
        {
            for (DateTime i = start; i < end; i = i.AddDays(1))
            {
                yield return i;
            }
        }

DateTime startingDate = DateTime.Parse("07/25/2018");//TODO Insert variable from poted form 

var numOfWeekends = GetDaysBetween(startingDate, startingDate.AddDays(7))
            .Where(d => d.DayOfWeek == DayOfWeek.Saturday || d.DayOfWeek == DayOfWeek.Sunday).Count();

startingDate = startingDate.AddDays(numOfWeekends);
            Console.WriteLine(startingDate);

Answer 3

我不太了解addintion部分，但是这段代码将为您提供一个没有任何星期日或星期六的列表：

DateTime startingDate = DateTime.Parse("07/25/2018");//TODO Insert variable from poted form 
DateTime endingDate = DateTime.Parse("07/08/2018");//TODO Insert variable from posted form

List<DateTime> dates = new List<DateTime>();

for (DateTime dt = startingDate; dt <= endingDate; dt = dt.AddDays(1))
    if (dt.DayOfWeek != DayOfWeek.Saturday && dt.DayOfWeek != DayOfWeek.Sunday)
        dates.Add(dt);

如果需要，您还可以添加一个计数器：

DateTime startingDate = DateTime.Parse("07/25/2018");//TODO Insert variable from poted form 
DateTime endingDate = DateTime.Parse("07/08/2018");//TODO Insert variable from posted form

List<DateTime> dates = new List<DateTime>();
int couter = 0;

for (DateTime dt = startingDate; dt <= endingDate; dt = dt.AddDays(1))
{
    if (dt.DayOfWeek != DayOfWeek.Saturday && dt.DayOfWeek != DayOfWeek.Sunday)
        dates.Add(dt);

    else
        counter++;
}

还有其他什么...

从日期范围中删除周末

3 个答案: