Question

我怎样才能将表't2'的'col'字段与作为记录的a，b，c，d均等地分为两个相等的字段：Col1（a，b）和Col2（c，d）？

表：t2

Col
A 
B
C
D

输出：

Col1 Col2
 A     C
 B     D

这是我尝试过的：

SELECT a.col1, "" as col2
FROM (SELECT  Top 50 Percent Col as Col1 From t2 order by Col ASc) as a

Union all

SELECT "", b.col1
FROM (SELECT  top 50 Percent Col as Col1 From t2 order by Col Desc) as b

上面的输出

col1    col2
a   
b   
         d
         c

我目前只能到达（女士访问权限）。非常感谢您的帮助。

创建表“ t2”

Create Table t2(Col  Char)

插入值

INSERT INTO t2 ([Col]) VALUES ("a")
INSERT INTO t2 ([Col]) VALUES ("b")
INSERT INTO t2 ([Col]) VALUES ("c")
INSERT INTO t2 ([Col]) VALUES ("d")

Answer 1

是的，如果您有一个顺序ID，则可以使用交叉表：

TRANSFORM 
    First(T.Col) AS Col
SELECT 
    ([ID]+1)\2 AS DualID
FROM 
    (SELECT ID, [ID] Mod 2 AS ColID, [Col]
    FROM YourTable) AS T
GROUP BY 
    ([ID]+1)\2
PIVOT 
    T.ColID;

Answer 2

SELECT A1.COL1 &  "-" & B1.COL1 AS PAIRS
FROM 
(SELECT TOP 50 PERCENT A.Col AS COL1 FROM t2 AS A ORDER BY A.Col ASC) AS A1 
INNER JOIN 
(SELECT TOP 50 PERCENT B.Col AS COL1 FROM t2 AS B ORDER BY B.Col DESC) AS B1 
ON A1.COL1 <> B1.COL1
WHERE  (SELECT COUNT(*) FROM t2 AS C WHERE C.Col < A1.COL1) = (SELECT 
COUNT(*) FROM t2 AS D WHERE D.Col > B1.COL1)

将一个字段平均分为2

2 个答案: