我在解析来自Web服务的数据时遇到问题,似乎可解码协议无法解析此json
这是我使用泛型解析的数据。
public func requestGenericData<T: Decodable>(urlString: String, httpMethod: String?, token: String!, completion: @escaping(T) ->()) {
let fullStringUrl = url + urlString
guard let url = URL(string: fullStringUrl) else { return }
guard let token = token else { return }
var urlRequest = URLRequest(url: url)
urlRequest.setValue("application/json", forHTTPHeaderField: "accept")
urlRequest.setValue("Bearer \(token)", forHTTPHeaderField: "Authorization")
urlRequest.httpMethod = httpMethod
URLSession.shared.dataTask(with: urlRequest) { (data, response, error) in
if self.isInternetAvailable() {
guard let data = data else { return }
if let httpResponse = response as? HTTPURLResponse {
if httpResponse.statusCode >= 200 && httpResponse.statusCode < 300 {
do {
let obj = try JSONDecoder().decode(T.self, from: data)
completion(obj)
} catch {
print("Error: \(String(describing: error))\n StatusCode: \(httpResponse.statusCode)")
}
}
}
} else {
showAlert(title: "No Internet Connect", message: "Please open your network and try again.", alertStyle: .alert, buttonTitle: "OK", buttonStyle: .default)
return
}
}.resume()
}
这是我的模特
struct JobWithCategory: Decodable {
let jobTypeID: Int
let jobCategoryID: Int
let name: String
let getJobs: [getJobs]
}
struct getJobs: Decodable {
let name: String
let description: String
}
struct JobCategories: Decodable {
let jobCategories: [JobWithCategory]
}
apiHelper.requestGenericData(urlString: "url/on/something/else", httpMethod: "GET", token: token) { (jobCategories: [JobCategories]) in
print(jobCategories)
}
现在我在控制台上遇到了这个问题:
错误:typeMismatch(Swift.Array,Swift.DecodingError.Context(codingPath:[],debugDescription:“预期对Array进行解码,但找到了一个字典。”,底层错误:无))
我的实现遗漏了什么或做错了什么?有人可以帮我解决这个问题,所以请详细说明为什么会这样,以便我可以很好地掌握代码中发生的事情。
预先感谢:)
答案 0 :(得分:0)
因为您使用
[JobCategories]
因为补全T
推断为数组,所以
T.self = [JobCategories].self
不是字典,请尝试
apiHelper.requestGenericData(urlString: "url/on/something/else",
httpMethod: "GET", token: token) { (jobCategories:JobCategories) in
print(jobCategories.jobCategories)
}
答案 1 :(得分:0)
请阅读错误消息
打算对Array进行解码,但是找到了一个字典
期望侧显示您的操作(错误),找到侧显示实际的类型。
就Decodable
而言,字典是一个结构。所以是
...{ (jobCategories: JobCategories) in