Question

我有此功能

  Meteor.robot.find({}, { _id: 1 }).forEach(function (robot) { x.push(robot.emails) })

将显示：

 [ { address: 'robot1@rob.fr', working: false } ],
I20180725-16:58:32.924(2)?   [ { address: 'rob2@rob.com', working: true } ],
I20180725-16:58:32.924(2)?   [ { address: 'ROB4@rob.fr', working: false } ],
I20180725-16:58:32.924(2)?   [ { address: 'rob5@rob.com', working: false } ]
 ]

humans.json

    {
        "_id": "22YAE7bEXdST9MyrZ",
        "createdAt": {
            "$date": "2016-11-22T15:09:25.968Z"
        },
        "abilities": {
            "power": {
            "mana":78,
            "chakra":0
            "energy":60
}
        },
        "emails": [
            {
                "address": "Rob6@rob.com",
                "working": false
            }
        ],
        "roles": [
           "killing":true
]
    }

我只想获取以大写字母开头的地址，而不是address + working属性。像这样。

['ROB4@rob.fr']

Answer 1

如果只是获取地址，只需通过循环访问电子邮件中的address属性。

Meteor.robot.find({}, { _id: 1 }).forEach(function (robot) {
    var addresses = [];
    robot.emails.forEach(function(element) {
        if (typeof element.address != undefined) {
            addresses[] = element;
        }
    });
    x.push(addresses);
})

Answer 2

这应该有效。

Meteor.robot.find({''}, { _id: 1 }).forEach(function (robot) { 
if(robot.emails){
    for(var i = 0; i<robot.emails.length; i++){
       var email = robot.emails[i];
       var emailAddress = email.address;
       if(emailAddress && emailAddress.charCodeAt(0) >= 65 && emailAddress.charCodeAt(0) <= 90){
             // pushing only when email address starts with Uppercase.
             x.push(email.address);
        }
    }
});

Answer 3

因此，由于robot.emails是一个数组，所以简单的解决方案是遍历emails数组，只返回地址，而不返回working属性。

要实现此目的，例如，您可以使用.map：

Meteor.robot.find({''}, {
    _id: 1
}).forEach(function (robot) {
    // only returns the address part of the robot object
    x.push(robot.emails.map(email => { return { address: email.address }; }))
});

卡住了嵌套数组中的元素

3 个答案: