Question

我有一个这样的记录：

$queryReplies

我想让用户在2018年7月1日至2018年7月5日之间拥有完善的有效记录。具有空值的“有效”列将被忽略。

预期结果：

mysql_stmt

之所以未选择userId＃2，是因为userId＃2具有2个“有效”列值，而不是等于0。

Answer 1

您可以使用EXISTS使用以下解决方案：

SELECT DISTINCT userId 
FROM records r1
WHERE NOT EXISTS (
    SELECT userId 
    FROM records r2
    WHERE r1.userId = r2.userId AND IFNULL(valid, 1) = 0 AND `date` BETWEEN '2018-07-01' AND '2018-07-05'
) AND NOT valid IS NULL AND `date` BETWEEN '2018-07-01' AND '2018-07-05';

演示： https://www.db-fiddle.com/f/jzh4cEoYXVKfvs6ZmSVhfG/1

Answer 2

尝试一下：

SELECT userId FROM table 
WHERE (date BETWEEN '2018-07-01' AND '2018-07-05') 
AND valid IS NOT NULL 
GROUP BY userId

Answer 3

如何测试NULL值？

无法使用比较运算符（例如=，<或<>）测试NULL值。

我们将不得不使用IS NULL和IS NOT NULL运算符。

SELECT userId FROM `user` WHERE (date BETWEEN '2018-07-01' AND '2018-07-05')  AND `user.valid` != '0' AND `valid` IS NOT NULL GROUP BY `userId`;

Answer 4

您可以使用not in运算符

  SELECT DISTINCT userId 
    FROM your_table t1 
    WHERE  userId not in (
        SELECT userId FROM your_table t2 WHERE t1.userId = t2.userId AND 
      valid =0 AND date >= '2018-07-01' and date<= '2018-07-05'
    )

http://sqlfiddle.com/#!9/8b8a9d/1

Answer 5

尝试以下查询：

SELECT DISTINCT userId 
FROM records r1
where 0 not in (
  SELECT valid
  FROM records r2
  WHERE r1.userId = r2.userId 
  AND   valid is not null 
  AND   `date` BETWEEN '2018-07-01' AND '2018-07-05'
  having count(*) > 0
);

也请here对其进行检查。

注意：如果将模式设置为Only-Group-By，则需要更改模式才能在查询中起作用。

尽管如此，以下查询不需要更改任何设置。您可以直接运行它。

SELECT DISTINCT userId 
FROM records r1
where valid is not null
group by userid
having count(*) > 0
and 0 not in ( SELECT valid
               FROM records r2
               WHERE r1.userId = r2.userId 
               AND   valid is not null 
               and   `date` BETWEEN '2018-07-01' AND '2018-07-05'
             )

这是此特定查询的fiddle

希望有帮助！

Answer 6

我看到SO仍然非常是一种代码编写服务。好吧，这是另一所老学校，鱼...

SELECT DISTINCT x.userid
  FROM records x
  LEFT
  JOIN records y
    ON y.userid = x.userid
   AND y.valid = 0
   AND y.date BETWEEN '2018-07-01' AND '2018-07-05'
 WHERE x.date BETWEEN '2018-07-01' AND '2018-07-05'
   AND y.userid IS NULL;

使用mysql获取在日期范围内具有有效记录的用户

6 个答案: