Question

付款明细表

payment_detail_id| payment_id | payment_status | total | user_id | company_id
10001            |          10|    1           | 100        1          103
10002            |          11|    2           | 200        1          103
10003            |          12|    2           | 300        2          104
10004            |          13|    1           | 400        2          104
10005            |          14|    0           | 500        1          105
10006            |          15|    2           | 600        1          103

付款表

payment_id| payment_type| 
10        |          1  |    
11        |          1  |    
12        |          1  |    
13        |          1  |    
14        |          0  |    
15        |          0  |

如何从user_id获取具有{{1}的payment_type和1的{{1}}的{{1}}？

目的是要发现他们已经进行了两种付款，对于已经付款两次的人，他们必须拥有payment_type中的0，但是如果例如，如果Payment_Table为payment_status，而2为user_id，则输出必须为1。

这个拥有company_id的用户拥有103 100+200+600=900和company_id，并且对于这两个条件payment_Type已成功完成0的用户的1中，即使之前付款失败

例如，(payment_type=1 and payment_type=0)是payment_Status的{{1}}是2。

Answer 1

SELECT
  DISTINCT user_id
FROM
  Payment_Detail_Table D
WHERE
  EXISTS(
    SELECT
      *
    FROM
      Payment_Table P1
    WHERE
      P1.payment_id = D.payment_id
    AND
      P1.payment_type = 1
  )
AND
  EXISTS(
    SELECT
      *
    FROM
      Payment_Table P2
    WHERE
      P2.payment_id = D.payment_id
    AND
      P2.payment_type = 0
   )

Answer 2

这是您要寻找的吗？

<svg width='64px' height='64px' xmlns="http://www.w3.org/2000/svg" viewBox="0 0 100 100" preserveAspectRatio="xMidYMid" class="uil-default"><rect x="0" y="0" width="100" height="100" fill="none" class="bk"></rect><rect  x='46' y='35' width='8' height='30' rx='5' ry='5' fill='#666666' transform='rotate(0 50 50) translate(0 -30)'>  <animate attributeName='opacity' from='1' to='0' dur='1s' begin='0s' repeatCount='indefinite'/></rect><rect  x='46' y='35' width='8' height='30' rx='5' ry='5' fill='#666666' transform='rotate(36 50 50) translate(0 -30)'>  <animate attributeName='opacity' from='1' to='0' dur='1s' begin='0.1s' repeatCount='indefinite'/></rect><rect  x='46' y='35' width='8' height='30' rx='5' ry='5' fill='#666666' transform='rotate(72 50 50) translate(0 -30)'>  <animate attributeName='opacity' from='1' to='0' dur='1s' begin='0.2s' repeatCount='indefinite'/></rect><rect  x='46' y='35' width='8' height='30' rx='5' ry='5' fill='#666666' transform='rotate(108 50 50) translate(0 -30)'>  <animate attributeName='opacity' from='1' to='0' dur='1s' begin='0.3s' repeatCount='indefinite'/></rect><rect  x='46' y='35' width='8' height='30' rx='5' ry='5' fill='#666666' transform='rotate(144 50 50) translate(0 -30)'>  <animate attributeName='opacity' from='1' to='0' dur='1s' begin='0.4s' repeatCount='indefinite'/></rect><rect  x='46' y='35' width='8' height='30' rx='5' ry='5' fill='#666666' transform='rotate(180 50 50) translate(0 -30)'>  <animate attributeName='opacity' from='1' to='0' dur='1s' begin='0.5s' repeatCount='indefinite'/></rect><rect  x='46' y='35' width='8' height='30' rx='5' ry='5' fill='#666666' transform='rotate(216 50 50) translate(0 -30)'>  <animate attributeName='opacity' from='1' to='0' dur='1s' begin='0.6s' repeatCount='indefinite'/></rect><rect  x='46' y='35' width='8' height='30' rx='5' ry='5' fill='#666666' transform='rotate(252 50 50) translate(0 -30)'>  <animate attributeName='opacity' from='1' to='0' dur='1s' begin='0.7s' repeatCount='indefinite'/></rect><rect  x='46' y='35' width='8' height='30' rx='5' ry='5' fill='#666666' transform='rotate(288 50 50) translate(0 -30)'>  <animate attributeName='opacity' from='1' to='0' dur='1s' begin='0.8s' repeatCount='indefinite'/></rect><rect  x='46' y='35' width='8' height='30' rx='5' ry='5' fill='#666666' transform='rotate(324 50 50) translate(0 -30)'>  <animate attributeName='opacity' from='1' to='0' dur='1s' begin='0.9s' repeatCount='indefinite'/></rect></svg>

查询未返回正确的数据

2 个答案: