我使用https://github.com/xmartlabs/XLPagerTabStrip,我有3个孩子……我想将价值从一个孩子传递到另一个孩子..
能够像这样将值从父级传递给第一个孩子:
let parentVC = self.parent as! ParentViewController
mobile = parentVC.mobile
但是现在我想将其从孩子1传递给孩子2 ..尝试了以上操作,但我发现移动电话无效
,父视图中的移动设备声明如下:
var mobile = ""
我如何在孩子之间传递数据?
override func viewControllers(for pagerTabStripController: PagerTabStripViewController) -> [UIViewController] {
let child1 = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "cominfo")
let child2 = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "comedu")
let child3 = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "comcv")
return [child1,child2,child3]
}
答案 0 :(得分:1)
override func viewControllers(for pagerTabStripController: PagerTabStripViewController) -> [UIViewController] {
let child1 = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "cominfo") as! yourChildClassname
child1.mobile = self.mobile
let child2 = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "comedu")as! yourChildClassname
child2.mobile = self.mobile
let child3 = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "comcv") as! yourChildClassname
child3.mobile = self.mobile
return [child1,child2,child3]
}