我想使用daterangepicker获取月份的最后一天。
这是我的剧本:
$('input[name="enddate"]').daterangepicker({
singleDatePicker: true,
showDropdowns: true,
isInvalidDate: function( date ) {
if( date.date() === getLastDayOfYearAndMonth(date.getFullYear(), date.getMonth()) ) {
return false;
} else {
return true;
}
},
locale: {
format: 'DD-MMM-YY'
}
});
function getLastDayOfYearAndMonth(year, month) {
return(new Date((new Date(year, month + 1, 1)) - 1)).getDate();
}
答案 0 :(得分:0)
尝试使用月和年获取最后的日期:
console.log(getLastDayOfYearAndMonth(2018, 2));
function getLastDayOfYearAndMonth(year, month)
{
var d = new Date(year, month, 0);
var lastdate =d.getDate() + '/' + (d.getMonth()+1) + '/' + d.getFullYear();
return lastdate;
}
修改后的答案:27-7-2018:
月+ 1表示如果选择2月,则将花费2月+ 1 = march,因此所需时间少于3月的第一天,因此将day参数设置为0意味着比该月的第一天少一天 上个月的最后一天
jQuery(function($) {
$('input[name="daterange"]').daterangepicker({
singleDatePicker: true,
showDropdowns: true,
isInvalidDate: function( date ) {
var mydate = new Date(date);
var lastday = getLastDayOfYearAndMonth(mydate.getFullYear(), mydate.getMonth());
if( date.date() === lastday) {
return false;
} else {
return true;
}
},
locale: {
format: 'DD-MMM-YY'
}
});
//alert(getLastDayOfYearAndMonth('2018', '07'));
function getLastDayOfYearAndMonth(year, month)
{
var d = new Date(year, month+1, 0);
var lastdate =d.getDate();
return lastdate;
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js">
</script>
<script src="https://cdn.jsdelivr.net/momentjs/latest/moment.min.js"></script>
<script src="https://cdn.jsdelivr.net/bootstrap.daterangepicker/2/daterangepicker.js"></script>
<link href="https://cdn.jsdelivr.net/bootstrap.daterangepicker/2/daterangepicker.css" rel="stylesheet"/>
<input type="text" name="daterange" />
答案 1 :(得分:0)
console.log(getLastDay(2018,7));
function getLastDay(year,month) {
// GET THE MONTH AND YEAR OF THE SELECTED DATE.
var LastDay = new Date(year, month + 1, 0);
// FINALLY, GET THE DAY.
var weekday = new Array();
weekday[0] = "Sunday";
weekday[1] = "Monday";
weekday[2] = "Tuesday";
weekday[3] = "Wednesday";
weekday[4] = "Thursday";
weekday[5] = "Friday";
weekday[6] = "Saturday";
return weekday[LastDay.getDay()] +' (' +
LastDay.toDateString('dd/mon/yyyy') + ')';
}