Question

如何从对象排序数组？代码：

         let A = [ { text: '故事', value: 'story', },
                   { text: '诗歌', value: 'poetry', },
                   { text: '励志', value: 'inspirational', }
                 ];
         // array B from backend** 
         let B = { 
                   story: 2,
                   poetry: 34,
                   inspirational: 30,
                 };

我想要这个：

             [ 
               { text: '诗歌', value: 'poetry', },
               { text: '励志', value: 'inspirational'},
               { text: '故事', value: 'story', }, 
             ];

Answer 1

只需使用JavaScript sort函数。

注意：：对数字进行排序时，您可以简单地使用紧凑比较：

紧凑比较： myArray.sort（（n1，n2）=> n1-n2）;

let A = [ { text: '故事', value: 'story', },
                   { text: '诗歌', value: 'poetry', },
                   { text: '励志', value: 'inspirational', }
                 ];
         // array B from backend** 
         let B = { 
                   story: 2,
                   poetry: 34,
                   inspirational: 30,
                 };
 A.sort((a, b) => B[b.value]-B[a.value] );
                 console.log(A);

Answer 2

您可以在$reference = Import-Csv -Path D:\corpold.csv $lookup = $reference | Group-Object -AsHashTable -AsString -Property EMPID $results = Import-Csv -Path D:\corpnew.csv | foreach { $email = $_.EMAIL_ADDRESS $status = $_.ACTIVE $fs = $_.FIRST_NAME $ls = $_.LAST_NAME $id = $_.EMPID $title = $_.JOB_TITLE $code = $_.JOB_CODE $type = $_.USER_TYPE $designee = $_.DESIGNEE $stores = $_.STORES $hiredate = $_.HIRE_DATE $dept = $_.DEPARTMENT $grp = $_.GROUP if ($lookup.ContainsKey($id)) { # if exists in yesterdays file # trying to figure out how to compare and only provide results into # the Export-Csv that have changed while excluding any items in # corpold that do not exist in corpnew } else { # if it does not exist update all fields [PSCustomObject]@{ ACTIVE = $status EMAIL_ADDRESS = $email FIRST_NAME = $fs LAST_NAME = $ls EMPID = $id JOB_TITLE = $title JOB_CODE = $code USER_TYPE = $type DESIGNEE = $designee STORES = $stores HIRE_DATE = $hiredate DEPARTMENT = $dept GROUP = $grp } } } # Sample outputs $results $results | Export-Csv -Path D:\delta.csv -NoTypeInformation中使用箭头功能作为自定义比较器。反向排序是通过索引array.sort对象以检索比较元素的排序值并从B中减去a的值来完成的。

Answer 3

您可以使用let A = [ { text: '故事', value: 'story', }, { text: '诗歌', value: 'poetry', }, { text: '励志', value: 'inspirational', } ]; let B = { story: 2, poetry: 34, inspirational: 30, }; const sorted = A.sort((a, b) => B[b.value] - B[a.value]); console.log(sorted);来排列数组元素。如果sort()上不存在value，则可以使用Number.NEGATIVE_INFINITY作为默认值。这会将未定义的值放在最后。

Answer 4

尝试一下，它使用箭头功能和let A = [{"text":"诗歌","value":"poetry"},{"text":"励志","value":"inspirational"},{"text":"故事","value":"story"}]; let B = {"story":2,"poetry":34,"inspirational":30}; A.sort((x, y) => (B[y.value] || Number.NEGATIVE_INFINITY) - (B[x.value] || Number.NEGATIVE_INFINITY)); console.log(A);：

array.sort

Answer 5

使用功能Array.prototype.sort，可以完成所需的输出。

此B[bV] - B[aV]将返回小于0或大于0或等于0的值，这是函数sort期望得到的值根据对象B中的值将元素定位在特定索引处。

let A = [{    text: '故事',    value: 'story',  },  {    text: '诗歌',  value: 'poetry',  },  {    text: '励志',    value: 'inspirational',  }],
    B = {  story: 2,  poetry: 34,  inspirational: 30};
A.sort(({value: aV}, {value: bV}) => B[bV] - B[aV]);

console.log(A);

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如何从对象排序数组？

5 个答案: