Question

我在Windows窗体应用程序中单击一个按钮，它会打开一个文件打开框。我单击要打开的xml文件，并希望数据填充Windows窗体中的文本字段，但出现System.ArgumentException：“路径中包含非法字符”。错误在FileStream代码行上。

private void button2_Click(object sender, EventArgs e)
{
    // On click Open the file
    if (openFileDialog1.ShowDialog() == DialogResult.OK)
    {
        StreamReader sr = new StreamReader(openFileDialog1.FileName);
        XmlSerializer serializer = new XmlSerializer(typeof(ContactLead));

        // Save file contents to variable
        var fileResult = sr.ReadToEnd();
        FileStream myFileStream = new FileStream(fileResult, FileMode.Open, FileAccess.Read, FileShare.Read);

        ContactLead contactLead = (ContactLead)serializer.Deserialize(myFileStream);

        this.textboxFirstName.Text = contactLead.firstname;
        this.textboxLastName.Text = contactLead.lastname;
        this.textboxEmail.Text = contactLead.email;
    }
}

Answer 1

这是您的问题：

var fileResult = sr.ReadToEnd();
FileStream myFileStream = new FileStream(fileResult, FileMode.Open, FileAccess.Read, FileShare.Read);

您正在读取一个文件的内容，然后将该文件的内容用作FileStream的文件名。当然，该文件的XML内容在Windows或任何操作系统上都不是有效的文件名。

我怀疑您真的只是想这样做：

private void button2_Click(object sender, EventArgs e)
{
    // On click Open the file
    if (openFileDialog1.ShowDialog() == DialogResult.OK)
    {
        // open the file for reading
        using (FileStream myFileStream = new FileStream(openFileDialog1.FileName, FileMode.Open, FileAccess.Read, FileShare.Read))
        {
            XmlSerializer serializer = new XmlSerializer(typeof(ContactLead));
            // deserialize the contact from the open file stream
            ContactLead contactLead = (ContactLead)serializer.Deserialize(myFileStream);

            this.textboxFirstName.Text = contactLead.firstname;
            this.textboxLastName.Text = contactLead.lastname;
            this.textboxEmail.Text = contactLead.email;
        }
    }
}

我已经自由地在using周围添加了FileStream，以便在您完成对它的读取之后将其正确处理（否则C＃将使文件保持打开状态。） / p>

单击按钮，打开xml文件，将数据显示到文本框

1 个答案: