深度合并哈希（添加值）

Question

我需要合并几个哈希。我的意思是：

a = {:x => 72, :y => 2}
b = {:x => 34, :y => 24}
c = a.deep_merge!(b) 

，c是{:x => 106, :y => 26}。

Crystal中的功能是否像Ruby中的deep_merge一样？

编辑：实际的hash是更多复杂

{"request" => {"duration" => 15100012.0, "total" => 252562.0, "per_second" => 16725.0, "bytes" => 43440664.0}, "error" => {"socket" => 0.0, "read" => 25.0, "write" => 0.0, "http" => 0.0, "timeout" => 0.0}, "latency" => {"minimum" => 234.0, "maximum" => 219466.0, "average" => 7640.0, "deviation" => 12940.0}, "percentile" => {"fifty" => 2732.0, "ninety" => 20335.0, "ninety_nine" => 65824.0, "ninety_nine_ninety" => 199536.0}}

实际上，它是json转换为hash的{​​{1}}

我的最终目标是在循环中添加一个由该哈希值（添加的值）组成的新哈希值

Answer 1

您所描述的不是深度合并（递归操作），而是自定义合并策略。

可以通过以下方式调用Hash#merge来解决此问题：

a = {:x => 72, :y => 2}
b = {:x => 34, :y => 24}
c = a.merge(b) { |_, v1, v2| v1 + v2 }
pp c # => {:x => 106, :y => 26}