Question

   foreach ($graphEdge as $graphNode) {
    echo
      "<div class='form-check mb-3'>" .
        "<input type='radio' name='fb_profile' class='form-check-input' value='".$graphNode['name']."'>" .
        "<img class='mr-2' src='" . $graphNode['picture']['url'] . "'>" . 
        "<label class='form-check-label' for='fb_profile'>" . 
        $graphNode['name'] . '</label>' . 
      "</div>";

    echo "<input type='hidden' name='fb_access_token' value='" . $graphNode['access_token'] . "'>";
    echo "<input type='hidden' name='fb_id' value='" . $graphNode['id'] . "'>";
    }

正如标题所示，我有3个名为“ fb_id”的隐藏输入，当我在表单中进行POST时将始终检索最后的隐藏输入，而fb_access_token将始终正确进行POST。

Answer 1

好的。从对话中可以看出，您想要获取取决于radio的值。您可以这样操作：

foreach ($graphEdge as $graphNode) {
    echo
        "<div class='form-check mb-3'>" .
            "<input type='radio' name='fb_profile' class='form-check-input' value='".$graphNode['name']."'>" .
            "<img class='mr-2' src='" . $graphNode['picture']['url'] . "'>" . 
            "<label class='form-check-label' for='fb_profile'>" . 
    $graphNode['name'] . '</label>' . 
        "</div>";

   echo "<input type='hidden' name='fb_access_token[".$graphNode['name']."]' value='" . $graphNode['access_token'] . "'>";
   echo "<input type='hidden' name='fb_id[".$graphNode['name']."]' value='" . $graphNode['id'] . "'>";
}

然后您可以像这样通过radio值获取选定的值（假设您的表单发送POST请求）：

$profile = $_POST['fb_profile'];
$accessToken = $_POST['fb_access_token'][$profile];
$id = $_POST['fb_id'][$profile];

具有相同名称的多个隐藏输入，始终检索最后一个输入

1 个答案: