这是我的代码我试图在onClick上实现一个简单的菜单。菜单按钮没有响应。你能帮我解决一下错误吗?
package com.test;
import android.app.Activity;
import android.app.AlertDialog;
import android.content.DialogInterface;
import android.content.Intent;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuInflater;
import android.view.MenuItem;
import android.view.View;
import android.view.Window;
import android.widget.ImageView;
import android.widget.TextView;
public class menuitem extends Activity {
@Override
public boolean onCreateOptionsMenu(Menu menu) {
MenuInflater inflater = getMenuInflater();
inflater.inflate(R.menu.menuitem, menu);
return true;
}
public boolean onOptionsItemSelected(MenuItem item) {
// Handle item selection
switch (item.getItemId()) {
case R.id.About:
About();
return true;
case R.id.Exit:
Exit();
return true;
default:
return super.onOptionsItemSelected(item);
}
}
private void Exit() {
// TODO Auto-generated method stub
finish();
}
private void About() {
// TODO Auto-generated method stub
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setMessage("APPLICATION VERSION-- 1.6")
.setCancelable(false)
.setPositiveButton("Ok", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
dialog.cancel();
}
});
AlertDialog alert = builder.create();
}
}
答案 0 :(得分:1)
您只是创建对话框....您需要调用show()才能显示它..