将嵌套的序列化数据作为一个

时间:2018-07-25 04:04:50

标签: python django django-models django-rest-framework

实际回报

{
"store_product_mapping":{
  "master_product":{
    "name": "abc",
    "description": "xyz"
    }
  }
"selling_price": 445
}

序列化器如下:

class GrandParentSerializer(serializers.ModelSerializer):
  class Meta:
  model = Z
  fields = ('name', 'description')

class ParnetSerializer(serializers.ModelSerializer):
  master_product = GrandParentSerializer(many=False, read_only=False)
  class Meta:
  model = Y
  fields = ('master_product',)

class ChildSerializer(serializers.ModelSerializer):
  store_product_mapping = ParnetSerializer(many=False, read_only=False) 
  class Meta:
  model = X
  fields = ('store_product_mapping', 'selling_price')

Am使用嵌套的rest_framework.serializer.ModelSerializer从多个级别序列化数据,但作为响应,我需要像这样。我是否需要制作新字典并循环更新字典?还是有捷径可做?

{
"name": xyz
"description": abcd
"price": 10
}

1 个答案:

答案 0 :(得分:4)

您可以像这样使用source参数:

class ChildSerializer(serializers.ModelSerializer):
      name = serializers.CharField(source='store_product_mapping.master_product.name') 
      description = serializers.CharField(source='store_product_mapping.master_product.description') 

      class Meta:
          model = X
          fields = ('name', 'description', 'selling_price')