Question

如何在struct数组中的数组中排列元素？

with races as(
select "800m" race, "Rudisha" name,23.4 s1, 26.3 s2, 26.4 s3, 26.1 s4 union all
select "800m" race, "Makhloufi" name,24.5 , 25.4, 26.6, 26.1 union all
select "800m" race, "Murphy" name,23.9, 26.0, 27.0, 26.0 union all
select "800m" race, "Bosse" name,23.6, 26.2, 26.5, 27.1 union all
select "800m" race, "Rotich" name,24.7, 25.6, 26.9, 26.4 union all
select "800m" race, "Lewandowski" name,25.0, 25.7, 26.3, 27.2 union all 
select "800m" race, "Kipketer" name,23.2, 26.1, 27.3, 29.4 union all
select "800m" race, "Berian" name,23.7, 26.1, 27.0, 29.3
)

我尝试了以下查询，但是没有用。

select race,array(select x splits from unnest(arr.splits)x order by x )from
(select race,[struct(name as name, [s1,s2,s3,s4] as splits)]arr from races)

Answer 1

因此，您只需要在s1，s2，s3，s4列中排列值，以使它们在相同的s1，s2，s3，s4中排序？ -是的，您是正确的

以下是用于BigQuery标准SQL

#standardSQL
SELECT
  race,
  name,
  splits[OFFSET(0)] AS s1,
  splits[OFFSET(1)] AS s2,
  splits[OFFSET(2)] AS s3,
  splits[OFFSET(3)] AS s4
FROM (
  SELECT 
    race,
    name,
    ARRAY(SELECT s FROM UNNEST([s1, s2, s3, s4]) s ORDER BY s) splits
  FROM `project.dataset.races`
)

您可以使用下面的问题中的虚拟数据进行测试，操作

#standardSQL
WITH `project.dataset.races` AS (
  SELECT "800m" race, "Rudisha" name,23.4 s1, 26.3 s2, 26.4 s3, 26.1 s4 UNION ALL
  SELECT "800m" race, "Makhloufi" name,24.5 , 25.4, 26.6, 26.1 UNION ALL
  SELECT "800m" race, "Murphy" name,23.9, 26.0, 27.0, 26.0 UNION ALL
  SELECT "800m" race, "Bosse" name,23.6, 26.2, 26.5, 27.1 UNION ALL
  SELECT "800m" race, "Rotich" name,24.7, 25.6, 26.9, 26.4 UNION ALL
  SELECT "800m" race, "Lewandowski" name,25.0, 25.7, 26.3, 27.2 UNION ALL 
  SELECT "800m" race, "Kipketer" name,23.2, 26.1, 27.3, 29.4 UNION ALL
  SELECT "800m" race, "Berian" name,23.7, 26.1, 27.0, 29.3
)
SELECT
  race,
  name,
  splits[OFFSET(0)] AS s1,
  splits[OFFSET(1)] AS s2,
  splits[OFFSET(2)] AS s3,
  splits[OFFSET(3)] AS s4
FROM (
  SELECT 
    race,
    name,
    ARRAY(SELECT s FROM UNNEST([s1, s2, s3, s4]) s ORDER BY s) splits
  FROM `project.dataset.races`
)

结果/输出为

Row race    name        s1      s2      s3      s4   
1   800m    Murphy      23.9    26.0    26.0    27.0     
2   800m    Bosse       23.6    26.2    26.5    27.1     
3   800m    Lewandowski 25.0    25.7    26.3    27.2     
4   800m    Makhloufi   24.5    25.4    26.1    26.6     
5   800m    Rudisha     23.4    26.1    26.3    26.4     
6   800m    Kipketer    23.2    26.1    27.3    29.4     
7   800m    Berian      23.7    26.1    27.0    29.3     
8   800m    Rotich      24.7    25.6    26.4    26.9

如何在bigquery中的结构数组中的数组中排列元素

1 个答案: