在展开的图标窗口中时,C#托盘应用程序中的ContextMenuStrip无法正确反应

时间:2018-07-24 18:49:58

标签: c# windows visual-studio

我制作了一个带有图标的托盘应用程序,该图标会在“图标点击”上打开 ContextMenuStrip 。我有三个可以点击的 ToolStripMenuItem

只要直接可见图标,托盘应用程序就可以正常工作。但是,如果必须单击V形以展开不可见的托盘图标,则会遇到一个问题。 我可以通过单击项目打开菜单。如果单击 ToolStripMenuItems 之一,则托盘菜单会进入“扩展托盘图标”的背景,并且无法再单击。我该如何预防? 看来背景是在捕获点击,而不是开放形式。

这是菜单的代码。

class Menu
{
    private static ContextMenuStrip contextMenuStrip;
    private static NotifyIcon notifyIcon1 = new NotifyIcon();
    public Menu()  
    {
        notifyIcon1.Icon = new Icon("icon.ico");
        notifyIcon1.Text = "icon";
        contextMenuStrip = new ContextMenuStrip();
        ToolStripItem stripItem0 = new ToolStripMenuItem("open");
        contextMenuStrip.Items.AddRange(new ToolStripItem[] { stripItem0 });
        ToolStripItem stripItem1 = new ToolStripMenuItem("stop");
        stripItem1.Click += new EventHandler(ToggleTracking);
        contextMenuStrip.Items.AddRange(new ToolStripItem[] { stripItem1 });
        ToolStripItem line = new ToolStripSeparator();
        contextMenuStrip.Items.AddRange(new ToolStripItem[] { line });
        ToolStripItem stripItem2 = new ToolStripMenuItem("close");
        stripItem2.Click += new EventHandler(Close);
        contextMenuStrip.Items.AddRange(new ToolStripItem[] { stripItem2 });

        notifyIcon1.ContextMenuStrip = contextMenuStrip;
        //notifyIcon1.ContextMenu = contextMenu1;
        notifyIcon1.Click += new EventHandler(IconClick);
        notifyIcon1.Visible = true;
    }

    private void ToggleTracking(object Sender, EventArgs e)
    {
        ToolStripMenuItem stripItem1 = (ToolStripMenuItem)contextMenuStrip.Items[1];
        if (stripItem1.Text == "stop")
        {
            stripItem1.Text = "restart";
            Batch.StopTimer();
        }
        else
        {
            stripItem1.Text = "stop";
            Batch.RestartTimer();
        }
    }

    private void Close(object Sender, EventArgs e)
    {
        Application.Exit();
    }
    private void IconClick(object Sender, EventArgs e)
    {
        Control strip = Sender as Control;
        if (contextMenuStrip.Visible)
        {
            contextMenuStrip.Hide();
        }
        else
        {
            contextMenuStrip.Show(Cursor.Position);
        }
    }
}

1 个答案:

答案 0 :(得分:1)

我必须像这样使用BringToFront方法。

{
    contextMenuStrip.Show(Cursor.Position);
    contextMenuStrip.BringToFront();
}

https://msdn.microsoft.com/de-de/library/system.windows.forms.control.bringtofront(v=vs.110).aspx