我想用同一列上一行的字符串替换0。例如:谢菲尔德(Sheffield)下的0应该读为谢菲尔德(Sheffield)。我正在和熊猫一起工作。
file = file[['Branch', 'Type' ,'total']]
#replace NaN with 0
file.fillna(0).tail(6)
Out[48]:
Branch Type total
394 Sheffield Sum of Resend to Branch 0
395 0 Number of PV Enquiries 83
396 Wakefield Sum of Resend to Branch 0
397 0 Number of PV Enquiries 38
398 York Sum of Resend to Branch 1
399 0 Number of PV Enquiries 59
I have tried:
a) #create a series for that column and replace
branch = file.iloc[ :, 0]
branch.replace(0, branch(-1))
# why is this series not callable?
b)# I tried a loop in the dataframe
for item in file:
if "Branch" == 0:
replace(0, "Branch"[-1])
# I am unsure how to refer to the row above
答案 0 :(得分:2)
将replace
与方法ffill
一起使用
file_df['Branch'].replace(to_replace='0', method='ffill', inplace=True)
>>> file_df
Branch Type total
394 Sheffield Sum of Resend to Branch 0
395 Sheffield Number of PV Enquiries 83
396 Wakefield Sum of Resend to Branch 0
397 Wakefield Number of PV Enquiries 38
398 York Sum of Resend to Branch 1
399 York Number of PV Enquiries 59
或者,因为看起来您已经用NaN
取代了0
,所以您可以省略该步骤而只使用ffill
。 即,如果您的原始数据框看起来像:
>>> file_df
Branch Type total
394 Sheffield Sum of Resend to Branch 0
395 NaN Number of PV Enquiries 83
396 Wakefield Sum of Resend to Branch 0
397 NaN Number of PV Enquiries 38
398 York Sum of Resend to Branch 1
399 NaN Number of PV Enquiries 59
使用:
file_df['Branch'].ffill(inplace=True)
请注意,我调用数据框file_df
而不是file
是为了不掩盖内置的python