我有以下型号
来源:
public class Opportunity
{
public Guid Id { get; set; }
public string Name { get; set; }
public Guid QuotationId { get; set; }
public int? QuotationNumber { get; set; }
public int? QuotationVersionNumber { get; set; }
}
目标:
public class OpportunityDto
{
public Guid Id { get; set; }
public string Name { get; set; }
public List<QuotationDto> Quotations { get; set; }
}
public class QuotationDto
{
public Guid Id { get; set; }
public int Number { get; set; }
public int VersionNumber { get; set; }
}
我从数据库中获取的数据将与Opportunity模型保持一致,并且我的api公开了OpportunityDto模型。 因此,在我的自动映射器配置中,我有以下代码:
services
.AddSingleton(new MapperConfiguration(cfg =>
{
cfg.CreateMap<OpportunityDto, Opportunity>().ReverseMap();
cfg.CreateMap<QuotationDto, Quotation>().ReverseMap();
}).CreateMapper())
我要实现的是唯一机会的列表,每个机会将有一个嵌套的成员,该成员将具有报价单。 如何使自动映射器执行此分组?现在,从api返回的契机Dto的Quotations成员始终为空。
答案 0 :(得分:2)
您可以执行以下操作:
public static void InitialiseMapper()
{
Mapper.Initialize(cfg =>
{
cfg.CreateMap<IEnumerable<Opportunity>, OpportunityDto>()
.ForMember(x => x.Id, x => x.MapFrom(y => y.FirstOrDefault().Id))
.ForMember(x => x.Name, x => x.MapFrom(y => y.FirstOrDefault().Name))
.ForMember(x => x.Quotations,
x => x.MapFrom(y => Mapper.Map<IEnumerable<Opportunity>, IEnumerable<QuotationDto>>(y).ToArray()))
;
cfg.CreateMap<Opportunity, QuotationDto>()
.ForMember(x => x.Id, x => x.MapFrom(y => y.QuotationId))
.ForMember(x => x.Number, x => x.MapFrom(y => y.QuotationNumber))
.ForMember(x => x.VersionNumber, x => x.MapFrom(y => y.QuotationVersionNumber))
;
});
}
然后成功地知道如何进行映射,如以下测试所示:
[TestMethod]
public void TestMethod1()
{
var oppo1Guid = Guid.NewGuid();
var opportunities = new List<Opportunity>
{
new Opportunity
{
Id = oppo1Guid,
Name = "Mikeys Oppurtunity",
QuotationId = Guid.NewGuid(),
QuotationNumber = 169,
QuotationVersionNumber = 80,
},
new Opportunity
{
Id = oppo1Guid,
Name = "Mikeys Oppurtunity",
QuotationId = Guid.NewGuid(),
QuotationNumber = 170,
QuotationVersionNumber = 20,
}
};
var dtos = Mapper.Map<IEnumerable<Opportunity>, OpportunityDto>(opportunities);
var json = JsonConvert.SerializeObject(dtos, Formatting.Indented);
Console.WriteLine(json);
}
输出为
{
"Id": "623c17df-f748-47a2-bc7e-35eb124dbfa3",
"Name": "Mikeys Oppurtunity",
"Quotations": [
{
"Id": "ad8b31c2-6157-4b7f-a1f2-9f8cfc1474b7",
"Number": 169,
"VersionNumber": 80
},
{
"Id": "515aa560-6a5b-47da-a214-255d1815e153",
"Number": 170,
"VersionNumber": 20
}
]
}
答案 1 :(得分:1)
@Afflatus我想给你一个可以遵循的想法。我假设您基于服务变量使用AspNetCore。
您可以创建像这样的扩展方法,以稍后在services.RegisterMappingsWithAutomapper()
之类的ConfigurationServices上进行调用:
public static IServiceCollection RegisterMappingsWithAutomapper(this IServiceCollection services)
{
var mapperConfig = AutoMapperHelper.InitializeAutoMapper();
services.AddScoped<IMapper>(provider => new Mapper(mapperConfig));
return services;
}
InitializeAutoMapper如下:
public static class AutoMapperHelper
{
public static MapperConfiguration InitializeAutoMapper()
{
//Load here all your assemblies
var allClasses = AllClasses.FromLoadedAssemblies();
MapperConfiguration config = new MapperConfiguration(cfg =>
{
if (allClasses != null)
{
//here normally I add another Profiles that I use with reflection, marking my DTOs with an interface
cfg.AddProfile(new MappingModelsAndDtos(allClasses));
cfg.AddProfile(new MyCustomProfile());
}
});
return config;
}
}
现在您需要实施配置文件,在本例中为MyCustomProfile
public class ModelProfile : Profile
{
public ModelProfile()
{
//put your source and destination here
CreateMap<MySource, MyDestination>()
.ConvertUsing<MySourceToMyDestination<MySource, MyDestination>>();
}
}
然后您需要实现MySourceToMyDestination类。 贝娄是我在项目中如何使用它的代码示例
public class ApplicationModel2ApplicationDto : ITypeConverter<ApplicationModel, ApplicationDto>
{
public ApplicationDto Convert(ApplicationModel source, ApplicationDto destination, ResolutionContext context)
{
var mapper = context.Mapper;
try
{
destination = new ApplicationDto
{
ApplicationId = source.ApplicationId,
ApplicationName = source.ApplicationName,
Documents = mapper.Map<IEnumerable<DocumentDto>>(source.Documents),
Tags = mapper.Map<IEnumerable<TagInfoDto>>(source.TagInfos)
};
}
catch
{
return null;
}
return destination;
}
}
希望这会有所帮助