Question

我正在尝试完成我的任务，一直在挣扎。想法是选择报告类型A或T。从那里输入，一直输入整数，直到退出。退出后，它应打印出报告“ T”加在一起的整数总数；或对于报告“ A”，它应打印总数，以及输入的整数列表。

此刻我遇到的问题是报告“ T”，一旦我输入整数，什么也不会使其出错或退出。它一直不断地要求我输入另一个整数。然后从报告“ A”开始，我输入的每个整数都会出现“无效输入”。我敢肯定我的代码可能还有更多的问题，但目前无法解决。任何指针将不胜感激。谢谢

def adding_report(report):
    total = 0
    items = []
    while True:
        user_number = input("Enter an ingteger to add to the total or \"Q\" to quit: ")
        if report.upper == "A":
            if user_number.isdigit():
                total += int(user_number)
                items.append(user_number)
            elif user_number.upper() == "Q":
                break
            else:
                print("Invalid input\n")
        elif report.upper() == "T":
            if user_number.isdigit():
                total += int(user_number)
            elif user_number.upper() == "Q":
                break
        else:
            print("Invalid input\n")

report = input("Report types include All Items (\"A\") or Total Only (\"T\")\nPlease select report type \"A\" or \"T\": ")
while True:
    if report.upper() in "A T":
        adding_report(report)
    else:
        print ("Invalid input")
        report = input("Please select report type \"A\" or \"T\": ")

Answer 1

in运算符需要一个可能值的集合。使用

if report.upper() in ("A", "T")

或（更接近您的财产）

if report.upper() in "A T".split()

Answer 2

您的第一个问题在这一行：

    if report.upper == "A":

这总是计算为False，因为report.upper是一个函数对象，而不是一个值。您需要

    if report.upper() == "A":

返回值。您也可以很好地重命名输入变量并将其值替换为所需的内部变量：

report = input("Report types include All Items (\"A\") or Total Only (\"T\")\nPlease select report type \"A\" or \"T\": ")
report = report.upper()

这样可以节省您每次访问该字母时打给upper的麻烦和时间。

请仔细阅读您的代码以查找重复的项目和错别字；从长远来看，您会省去头痛-我从个人经验中知道。

Answer 3

尝试一下

def adding_report(report):
      total = 0
      items = []
      while True:
        user_number = input("Enter an integer to add to the total or \"Q\" to quit: ")
        #You used "report.upper" instead of "report.upper()"
        if report.upper() == "A":
            if user_number.isdigit():
                total += int(user_number)
                items.append(user_number)
            elif user_number.upper() == "Q":
                break
            else:
                print("Invalid input\n")
        elif report.upper() == "T":
            if user_number.isdigit():
                total += int(user_number)
                #You forgot ot add this : "items.append(user_number)"
                items.append(user_number)
            elif user_number.upper() == "Q":
                break
        else:
            print("Invalid input\n")
            break
#Add this for loop termination: "or 0 to quit: "
report = input("Report types include All Items (\"A\") or Total Only (\"T\")\nPlease select report type \"A\" or \"T\" Or 0 to quit: ")
while True:
    #it should be this ""if report.upper() in "A" or "T":"" not this ""if report.upper() in "A T":""
    if report.upper() in "A" or "T":
        adding_report(report)
    #The condition below terminates the program
    elif report == '0':
        break
    else:
        print("Invalid input")
    report = input("Please select report type \"A\" or \"T\": ")

Python while循环未按预期运行

3 个答案: