读取将引用和未引用内容混合到bash数组中的文件，保留引号

Question

我的文件看起来像

"dog" 23 "a description of the dog" 123 456 "21"
"cat"  5 "a description of the cat" 987 654 "22"

我正在将文件逐行加载到数组中

filename=$1

while read -r line
do
   animal_array=($line)
  *do stuff
done < $filename

我想看的东西

animal_array[1] --> "dog"
animal_array[2] --> 23
animal_array[3] --> "a description of the dog"
animal_array[4] --> 123
animal_array[5] --> 456
aninal_array[6] --> "21"

我得到的是

animal_array[1] --> "dog"
animal_array[2] --> 23
animal_array[3] --> "a  
animal_array[4] --> description
animal_array[5] --> of
animal_array[6] --> the
animal_array[7] --> dog"
animal_array[8] --> 123
animal_array[9] --> "21"

在将行读入数组之前，努力寻找一种检查“引号”的方法。引号必须在数组中。

Answer 1

如果您不打算保留引号作为数据，请改用Bash: Reading quoted/escaped arguments correctly from a string上的答案。

也就是说，如果您只需要处理带有文字数据的双引号字符串（没有转义FPAT，则GNU awk扩展\"可以用于您在此处请求的那种解析）内的引号或其他奇数）：

split_quoted_strings() {
  gawk '
    BEGIN {
      FPAT = "([^[:space:]\"]+)|(\"[^\"]+\")"
    }

    {
      printf("%d\0", NF)
      for (i = 1; i <= NF; i++) {
        printf("%s\0", $i)
      }
    }
  ' "$@"
}

# replace this with whatever you want to have called after a line has been read
handle_array() {
  echo "Read array with contents:"
  printf ' - %s\n' "$@"
  echo
}

while IFS= read -r -d '' num_fields; do
  array=( )
  for ((i=0; i<num_fields; i++)); do
    IFS= read -r -d '' piece
    array+=( "$piece" )
  done
  handle_array "${array[@]}"
done < <(split_quoted_strings)

...正确发出作为输出：

Read array with contents:
 - "dog"
 - 23
 - "a description of the dog"
 - 123
 - 456
 - "21"

Read array with contents:
 - "cat"
 - 5
 - "a description of the cat"
 - 987
 - 654
 - "22"