Question

我想要什么？从这个数组中，我们将其称为$forsend：

array(3) {
  [7493474]=>
  array(6) {
    ["id"]=>
    int(1414594)
    ["product_id"]=>
    int(1)
    ["ins_type"]=>
    string(4) "zzzz"
    ["phone"]=>
    string(10) "1111111111"
    ["exam_date"]=>
    string(10) "28.07.2018"
    ["status"]=>
    int(1)
  }
  [7578595]=>
  array(6) {
    ["id"]=>
    int(1414969)
    ["product_id"]=>
    int(1)
    ["ins_type"]=>
    string(4) "zzzz"
    ["phone"]=>
    string(10) "2222222222"
    ["exam_date"]=>
    string(10) "28.07.2018"
    ["status"]=>
    int(1)
  }
  [7583863]=>
  array(6) {
    ["id"]=>
    int(1415124)
    ["product_id"]=>
    int(1)
    ["ins_type"]=>
    string(4) "zzzz"
    ["phone"]=>
    string(10) "1111111111"
    ["exam_date"]=>
    string(10) "28.07.2018"
    ["status"]=>
    int(1)
  }
}

我想删除这些与同一部手机相同的记录（在这种情况下为1111111111，但可以有多个相同的记录），没有第一个记录 ，结果将是：

    array(2) {
      [7493474]=>
      array(6) {
        ["id"]=>
        int(1414594)
        ["product_id"]=>
        int(1)
        ["ins_type"]=>
        string(4) "zzzz"
        ["phone"]=>
        string(10) "1111111111"
        ["exam_date"]=>
        string(10) "28.07.2018"
        ["status"]=>
        int(1)
      }
      [7578595]=>
      array(6) {
        ["id"]=>
        int(1414594)
        ["product_id"]=>
        int(1)
        ["ins_type"]=>
        string(4) "ГО"
        ["phone"]=>
        string(10) "2222222222"
        ["exam_date"]=>
        string(10) "28.07.2018"
        ["status"]=>
        int(1)
      }
    }

我尝试了什么？ ..这段代码：

    foreach($forsend as $x) {
        var_dump($x);
        $foundKey = array_search($x['phone'], array_column($forsend, 'phone'));
        unset($forsend[$foundKey]);
    }

目前它不起作用，它找到了密钥，但没有将其删除，我也不知道为什么。

Answer 1

您可以尝试使用此代码，如果我正确理解您的需求，它应该可以工作。

<?php
$phones = [];
$final = [];
foreach($forsend as $key => $record) {
    if(!isset($phones[$record['phone']]))
        //reversing - now we have an array which is arranged using phone number as a key, 
        //meaning that only one record can exist with the same number
        $phones[$record['phone']] = $key; 
    else
        //if the record is repeated, remove the previous instance, and do not add this one 
        //to the array
        unset($phones[$record['phone']]);
}
foreach($phones as $phone){ 
    //reversing again, getting the format that was used before, from $phone the key of the 
    //top array is returned and using that key the data is taken from
    //$forsend and put to final
    $final[$phone] = $forsend[$phone];
}
print_r($final);

要保留具有相同手机的第一个元素，只需删除else中的if子句，该子句就足够了：

<?php
$phones = [];
$final = [];
foreach($forsend as $key => $record) {
    if(!isset($phones[$record['phone']]))
        $phones[$record['phone']] = $key;
}
foreach($phones as $phone){ 
    $final[$phone] = $forsend[$phone];
}
print_r($final);

在关联数组中搜索，然后删除相同值的元素？

1 个答案: