Question

早上好，我有一个简单的问题。我需要一个允许客户端将XML发送到服务器的套接字。我尝试发送一个简单的字符串b'simple string just for example'，并且一切正常，但是当我尝试发送XML（二进制）时，服务器无法将其记录下来。我将粘贴代码

客户

import socket

socket = socket.socket()
socket.connect(("localhost", 54610))
file = open(r"c:\shared\68118.xml", "rb")
stream = file.read(65536)
while stream:
    socket.send(stream)
    stream = file.read(65536) # tried with 1024, 2048
socket.close()

服务器

import socket

socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server_address = ('', 54610)
socket.bind(server_address)
socket.listen(1)

while True:
    inbound_stream, address = socket.accept()

    print(address)
    counter = 1
    file = open(r'c:\shared\68118_' + str(counter) + '.xml', 'wb')  # binary
    counter += 1
    while(True):
        stream = inbound_stream.recv(65536)
        while stream:
            file.write(stream)
            stream = inbound_stream.recv(65536) # tried with 1024, 2048
        file.close()
        inbound_stream.close()

socket.close() # TODO NOT REACHABLE

输出文件为68118_1.xml 0Kb，里面没有任何内容

我做错了什么？

提前谢谢

Answer 1

我刚刚从循环中删除了stream = file.read(65536) # tried with 1024, 2048，一切正常

通过python中的套接字的XML

1 个答案: