Question

使用正确的字段名称更新了脚本。为什么这不起作用？

<?php $con = mysql_connect("localhost","root","pass"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("bookorama", $con); $sql="SELECT * FROM customers"; $result = mysql_query($sql); // You actually have to execute the $sql with mysql_query(); echo "<table>"; //start the table while($row = mysql_fetch_array($result, MYSQL_ASSOC)) //Loop through the results { //echo each row of the table echo "<tr> <td>$row['customerID']</td> <td>$row['name']</td> <td>$row['Aaddress']</td> <td>$row['city']</td> </tr>"; } echo '</table>'; //close out the table ?>

Answer 1

您可以mysql_fetch_array或mysql_fetch_assoc从您的查询中检索行。

例如使用mysql_fetch_array：

$result = mysql_query($sql);
echo "<table><tbody>";
while ($row = mysql_fetch_array($result, MYSQL_NUM)) {
    echo "<tr><td>".$row[0] . "</td><td>" . $row[1] . "</td></tr>";  
}
echo "</tbody></table>"

Answer 2

<?php
$con = mysql_connect("localhost","root","pass");
if (!$con)
{
    die('Could not connect: ' . mysql_error());
}

mysql_select_db("bookorama", $con);

$sql="SELECT * FROM customers"; 
$result = mysql_query($sql);     // You actually have to execute the $sql with mysql_query();

echo "<table>";  //start the table

while($row = mysql_fetch_array($result, MYSQL_ASSOC))  //Loop through the results
{
    //echo each row of the table
    echo "<tr>";                              
    echo "<td>$row['CustomerID']</td>";
    echo "<td>$row['address']</td>";
    echo "<td>$row['city']</td>";
    echo "</tr>";
} 

echo '</table>';   //close out the table

?>

Answer 3

您需要运行查询并遍历结果。

你最好从第一天开始学习PDO。

并且也不要直接从任何用户提交的变量（包括$_POST）进行插值。

Answer 4

当在双引号中嵌入比标量更复杂的东西时，你肯定需要这样做

 echo "<tr>                              
        <td>{$row['CustomerID']}</td>
        <td>{$row['address']}</td>
        <td>{$row['city']}</td>
      </tr>";

因此，无论何时你的var名称都比引号中的“test $ var”更复杂，请用{}换行 - 即使这样，最好将标量包装成“test {$ var}”

使用php从mysql db获取信息

4 个答案: