Question

please can anyone help me with some code to get specific data from an array here's is my array

var array = [
  {
    "name": "Joe",
    "age": 17
  },
  {
    "name": "Bob",
    "age": 17
  },
  {
    "name": "Carl",
    "age": 35
  }
]

just want to return name and its values without returning age

thanks in advance.

Answer 1

尝试使用jQuery.inArray（）函数。希望对您有帮助。

   
    
    function functionname(){
     var names = [ {"name":"Joe", "age":17},{"name":"Bob", "age":17},{"name":"Carl", "age": 35}];
            var name = $('#name').val(); 
            if(jQuery.inArray(name, names)) {  
                alert(name +" Is In Array");  
            } else {  
                alert(name + ' Is NOT In Array...');  
            }  
    }

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" name="name" id="name"/>
    <button onclick="functionname()" >Submit</button>

Answer 2

Use Array.map() with array destructuring method so that you get only the name key-value. Array.map() will have only one parameter so you do not need to mention return there:

var array = [ {"name":"Joe", "age":17},{"name":"Bob", "age":17},{"name":"Carl", "age": 35}];
var res = array.map(({name}) => ({name}));
console.log(res);

Answer 3

Simple enough to access the name attribute of the object you simply need to reference the item in the array and select the name like so:

array[i].name;

Answer 4

您可以创建一个辅助函数来从该数组中获取一个按属性对象：

var persons = [
  {
    "name": "Joe",
    "age": 17
  },
  {
    "name": "Bob",
    "age": 17
  },
  {
    "name": "Carl",
    "age": 35
  }
];

function getElement(personList, property, comparable) {
  var arraySize = personList.length;
  for(var i = 0; i < arraySize; i++) {
     if (personList[i][property] == comparable) {
         return personList[i]
     }
  }
  return {"name":null, "age":null};
}

console.log(getElement(persons, "name", "Joe")); // outputs { "name": "John", "age" : 17}
console.log(getElement(persons, "name", "Fake John")); // outputs { "name": null, "age" :null}

通过这种方式，您可以通过他拥有的任何属性来检索您的人员对象。

Answer 5

You can use Array#map to do that. Destructure the name from the object and return a new object with only the name.

See the working demo below:

var array = [{
  "name": "Joe",
  "age": 17
}, {
  "name": "Bob",
  "age": 17
}, {
  "name": "Carl",
  "age": 35
}];

var result = array.map(({name, ...rest}) => ({name}));
console.log(result);

Answer 6

如果你只想要这个值，下面的例子只会给你一维数组中的名字

var array = [ {"name":"Joe", "age":17},{"name":"Bob", "age":17},{"name":"Carl", "age": 35}];
var res = array.map(({name}) => (name));
console.log(res);

Answer 7

所有这些Array.Map函数 facepalm

var array = [
  {
    "name": "Joe",
    "age": 17
  },
  {
    "name": "Bob",
    "age": 17
  },
  {
    "name": "Carl",
    "age": 35
  }
]

array.forEach((entry) => {
  console.log(entry.name) /* Do whatever you want with `entry.name` */
})

how to return a specific key from an array

7 个答案: