Question

我使用的C＃表达式库不会直接支持我的表/字段参数语法：

以下是不直接支持的表/字段参数名称：

TableName1.FieldName1
[TableName1].[FieldName1]
[Table Name 1].[Field Name 1]

它接受不带空格的字母数字参数，或大括号括在方括号内的大多数字符。我想使用C＃正则表达式将点分隔符和相邻括号替换为不同的分隔符，因此结果如下：

[TableName1|FieldName1]
[TableName1|FieldName1]
[Table Name 1|Field Name 1]

我还需要在单引号中跳过任何字符串文字，例如：

'TableName1.FieldName1'

当然，忽略任何数字文字，如：

12345.6789

编辑：感谢您就改进我的问题提出的反馈意见。希望现在更清楚了。

Answer 1

我已经写了一个全新的答案，现在澄清了问题：

你可以在一个正则表达式中执行此操作。我认为它非常防弹，但正如你所看到的，它并不是完全不言自明的，这就是为什么我自由地评论它。希望它有意义。

你很幸运，.NET允许重复使用已命名的捕获组，否则你将不得不分几步完成这项工作。

resultString = Regex.Replace(subjectString, 
    @"(?:             # Either match...
     (?<before>       #  (and capture into backref <before>)
      (?=\w*\p{L})    #  (as long as it contains at least one letter):
      \w+             #  one or more alphanumeric characters,
     )                #  (End of capturing group <before>).
     \.               #  then a literal dot,
     (?<after>        #  (now capture again, into backref <after>)
      (?=\w*\p{L})    #  (as long as it contains at least one letter):
      \w+             #  one or more alphanumeric characters.
     )                #  (End of capturing group <after>) and end of match.
    |                 # Or:
     \[               #  Match a literal [
     (?<before>       #  (now capture into backref <before>)
      [^\]]+          #  one or more characters except ]
     )                #  (End of capturing group <before>).
     \]\.\[           #  Match literal ].[
     (?<after>        #  (capture into backref <after>)
      [^\]]+          #  one or more characters except ]
     )                #  (End of capturing group <after>).
     \]               #  Match a literal ]
    )                 # End of alternation. The match is now finished, but
    (?=               # only if the rest of the line matches either...
     [^']*$           #  only non-quote characters
     |                # or
     [^']*'[^']*'     #  contains an even number of quote characters
     [^']*            #  plus any number of non-quote characters
     $                #  until the end of the line.
    )                 # End of the lookahead assertion.", 
    "[${before}|${after}]", RegexOptions.Multiline | RegexOptions.IgnorePatternWhitespace);

Answer 2

希望您可以尝试使用此正则表达式：/(\w[0-9]* *)+/g这会过滤掉除。之外的所有字母数字。

正则表达式在公式中查找分隔符点

2 个答案: