我有一个来自第三方的表格，我无法控制。每个地址字段都包含完整地址，包括邮政编码。每个地址都有动态数量的独立地址字段。我有一个Split（）TVF，它可以将地址字段拆分为单独的行。但是，当我将TVF表交叉应用回SELECT查询时，它将为TVF表中的每个ro返回一行。如何获得返回主表的一行并将TVLUM表中的行与COLUMNS分开的信息？
提供的地址示例：
a。 1街道，位置，城镇，县，邮政编码
b。 2建筑物，街道，城镇，邮政编码
c。街道，地区，乡镇，县，邮政编码3层3层
TVF使用“，”作为分隔符，将其作为每行一个值返回。然后，我需要将该数据作为每个地址字段的一列连接回原始数据。
这是我的选择查询：
select DISTINCT TOP 5 ttp.ProjectID
,cac.ID
,cac1.Proprietor1Address1
--,CASE WHEN addr.ID = 1 THEN addr.Data END AS Address1
FROM ArdentTest.ardent.LRTitlesToProcess ttp
JOIN LandRegistryData.landreg.CommercialandCorporateOwnershipData cac
ON ttp.TitleNo = cac.TitleNumber
JOIN (SELECT TitleNumber
,Proprietor1Address1
FROM LandRegistryData.landreg.CommercialandCorporateOwnershipData
WHERE 1 = 1
AND ISNULL(Proprietor1Address1, '') <> '') cac1
ON ttp.TitleNo = cac1.TitleNumber
CROSS APPLY DBAdmin.resource.Split(cac1.Proprietor1Address1, ', ') addr
WHERE 1 = 1
AND ttp.DateLRRequestSent IS NULL
AND cac.ID IN (50764, 78800, 157089, 206049, 449112)
ORDER BY 1
会产生以下结果：
ProjectID ID Proprietor1Address1
1010 50764 Bridge House, 1 Walnut Tree Close, Guildford, Surrey GU1 4LZ
1010 78800 Bridge House, 1 Walnut Tree Close, Guildford, Surrey GU1 4LZ
1010 157089 Bridge House, 1 Walnut Tree Close, Guildford, Surrey GU1 4LZ
1010 206049 Bridge House, 1 Walnut Tree Close, Guildford, Surrey GU1 4LZ
1010 449112 Church House, Great Smith Street, London SW1P 3AZ
我需要使用函数中的行将单独的地址列添加到结果集中，但我不知道该怎么做。
答案 0 :(得分：0)
如果您可以做一些假设，例如一个地址最多可以包含10个部分。您可以使用此脚本。我使用了STRING_SPLIT而不是您的拆分功能。
DECLARE @Table TABLE (Id INT, Address VARCHAR(500))
INSERT INTO @Table VALUES
(1, '1 The Street, The Locality, The Town, The County, The Postcode'),
(2, '2 The Building, The Street, The Town, The Postcode'),
(3, 'Floor 3, 3 The Street, The Locality, The Town, The County, The Postcode')
SELECT * FROM @Table T
CROSS APPLY(
SELECT * FROM (SELECT ROW_NUMBER()OVER(ORDER BY (SELECT NULL)) RN, * FROM STRING_SPLIT(T.Address, ',')) SRC
PIVOT (MAX(value) FOR RN IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10])) PVT
) X
结果：
Id Address 1 2 3 4 5 6 7 8 9 10
----------- -------------------------------------------------------------------------------- --------------------- --------------------- --------------------- --------------------- --------------------- --------------------- --------------------- --------------------- --------------------- ---------------------
1 1 The Street, The Locality, The Town, The County, The Postcode 1 The Street The Locality The Town The County The Postcode NULL NULL NULL NULL NULL
2 2 The Building, The Street, The Town, The Postcode 2 The Building The Street The Town The Postcode NULL NULL NULL NULL NULL NULL
3 Floor 3, 3 The Street, The Locality, The Town, The County, The Postcode Floor 3 3 The Street The Locality The Town The County The Postcode NULL NULL NULL NULL
答案 1 :(得分：0)
您可以从串联字符串中创建XML，并通过索引寻址每个部分
-表格（谢谢Serkan，我复制了您的DDL）
DECLARE @Table TABLE (Id INT, Address VARCHAR(500))
INSERT INTO @Table VALUES
(1, '1 The Street, The Locality, The Town, The County, The Postcode'),
(2, '2 The Building, The Street, The Town, The Postcode'),
(3, 'Floor 3, 3 The Street, The Locality, The Town, The County, The Postcode');
-此查询将逐个返回部分
WITH Splitted AS
(
SELECT *
,CAST('<x>' + REPLACE((SELECT [Address] AS [*] FOR XML PATH('')),',','</x><x>') + '</x>' AS XML) AsXml
FROM @Table
)
SELECT *
,AsXml.value('/x[1]','nvarchar(max)') AS Col1
,AsXml.value('/x[2]','nvarchar(max)') AS Col2
,AsXml.value('/x[3]','nvarchar(max)') AS Col3
,AsXml.value('/x[4]','nvarchar(max)') AS Col4
,AsXml.value('/x[5]','nvarchar(max)') AS Col5
,AsXml.value('/x[6]','nvarchar(max)') AS Col6
FROM Splitted
-结果
/*+----+----------------+--------------+--------------+--------------+--------------+--------------+
| ID | Col1 | Col2 | Col3 | Col4 | Col5 | Col6 |
+----+----------------+--------------+--------------+--------------+--------------+--------------+
| 1 | 1 The Street | The Locality | The Town | The County | The Postcode | NULL |
+----+----------------+--------------+--------------+--------------+--------------+--------------+
| 2 | 2 The Building | The Street | The Town | The Postcode | NULL | NULL |
+----+----------------+--------------+--------------+--------------+--------------+--------------+
| 3 | Floor 3 | 3 The Street | The Locality | The Town | The County | The Postcode |
+----+----------------+--------------+--------------+--------------+--------------+--------------+*/
-您可以在所有步骤上使用REVERSE。在所有情况下，这都将邮政编码放在首位（只要邮政编码是那里的最后一个元素）
WITH Splitted AS
(
SELECT *
,CAST('<x>' + REPLACE((SELECT REVERSE([Address]) AS [*] FOR XML PATH('')),',','</x><x>') + '</x>' AS XML) AsXml
FROM @Table
)
SELECT *
,REVERSE(AsXml.value('/x[1]','nvarchar(max)')) AS Col1
,REVERSE(AsXml.value('/x[2]','nvarchar(max)')) AS Col2
,REVERSE(AsXml.value('/x[3]','nvarchar(max)')) AS Col3
,REVERSE(AsXml.value('/x[4]','nvarchar(max)')) AS Col4
,REVERSE(AsXml.value('/x[5]','nvarchar(max)')) AS Col5
,REVERSE(AsXml.value('/x[6]','nvarchar(max)')) AS Col6
FROM Splitted;
-结果
/*+----+--------------+------------+------------+----------------+--------------+---------+
| ID | Col1 | Col2 | Col3 | Col4 | Col5 | Col6 |
+----+--------------+------------+------------+----------------+--------------+---------+
| 1 | The Postcode | The County | The Town | The Locality | 1 The Street | NULL |
+----+--------------+------------+------------+----------------+--------------+---------+
| 2 | The Postcode | The Town | The Street | 2 The Building | NULL | NULL |
+----+--------------+------------+------------+----------------+--------------+---------+
| 3 | The Postcode | The County | The Town | The Locality | 3 The Street | Floor 3 |
+----+--------------+------------+------------+----------------+--------------+---------+*/