Windows中的pthread_cond_timedwait

Question

我尝试在代码中实现pthread功能。不幸的是，我无法正确实现函数pthread_cond_timedwait（）。在Linux中，一切正常。但是在Windows中，此函数不会根据设置的超时返回。这是我的简单代码：

#define HAVE_STRUCT_TIMESPEC
#include <Windows.h>
#include <future>
#include <pthread.h>
#include <time.h>

pthread_mutex_t mutex;
pthread_cond_t condVar;

void * Engine(void *)
{
  unsigned long timeout = 5;
  printf("timeout: %d\n", timeout);
  struct timespec ts;
  memset(&ts, 0, sizeof ts);
  timespec_get(&ts, TIME_UTC);
  char buff[100];
  memset(&buff, 0, sizeof buff);
  strftime(buff, sizeof buff, "%D %T", gmtime(&ts.tv_sec));
  printf("ts: %s.%09ld\n", buff, ts.tv_nsec);
  ts.tv_sec += timeout;
  pthread_mutex_lock(&mutex);
  auto t1 = std::chrono::steady_clock::now();
  int rcTimedwait = pthread_cond_timedwait(&condVar, &mutex, &ts);
  auto t2 = std::chrono::steady_clock::now();
  pthread_mutex_unlock(&mutex);
  memset(&ts, 0, sizeof ts);
  timespec_get(&ts, TIME_UTC);
  memset(&buff, 0, sizeof buff);
  strftime(buff, sizeof buff, "%D %T", gmtime(&ts.tv_sec));
  printf("ts: %s.%09ld\n", buff, ts.tv_nsec);
  printf("duration %.0f\n", std::chrono::duration<double, std::milli>(t2 - t1).count());

  return 0;
}

int main()
{
  pthread_mutex_init(&mutex, NULL);
  pthread_cond_init(&condVar, NULL);
  int num1 = 1;
  pthread_t thread;
  pthread_create(&thread, NULL, Engine, &num1);
  char ch = 0;
  do
  {
    ch = getchar();
    Sleep(1);
  } while (ch != '.');
  pthread_detach(thread);
  pthread_cancel(thread);
  pthread_cond_destroy(&condVar);
  pthread_mutex_destroy(&mutex);

  return 0;
}

并输出：

timeout: 5
ts: 07/24/18 07:32:21.770438500
ts: 07/24/18 07:32:26.001352700
duration 4229

timeout: 5
ts: 07/24/18 07:47:41.510704900
ts: 07/24/18 07:47:46.001373600
duration 4488

timeout: 5
ts: 07/24/18 07:47:53.190739700
ts: 07/24/18 07:47:58.001629000
duration 4808