Question

我的字符串为日期介于2018年3月至2018年6月。
现在我将在2018年3月和2018年6月使用2个变量。现在我希望将o / p设置为

2018年3月
2018年4月
2018年5月
2018年6月

代码：

var temp="Date between March 2018 and June 2018";
var fields=temp.split(' ');
var date2=fields[fields.length-2] +" "+fields[fields.length-1];

var date1=fields[fields.length-5] +" "+fields[fields.length-4];
alert(date1);//March 2018
alert(date2);//June 2018

Answer 1

您可以为此使用moment.js：

const numberOfMonthsDiff = moment(date2).diff(moment(date1), 'months', true);

Documentation of the diff method。

默认情况下，moment＃diff会将结果截断为零小数位，返回一个整数。如果您想要一个浮点数，将true作为第三个参数传递。在2.0.0之前，moment＃diff返回a 四舍五入到最接近的整数，而不是四舍五入的数字。

JSFIDDLE Example

修改

我了解您想要以下月份：

var temp="Date between March 2018 and June 2018";
var fields=temp.split(' ');
var date2=fields[fields.length-2] +" "+fields[fields.length-1];
var date1=fields[fields.length-5] +" "+fields[fields.length-4];
const numberOfMonthsDiff = moment(date2).diff(moment(date1), 'months', true);

const dateToModify = moment(date1);
const monthsBetween = Array.from(Array(numberOfMonthsDiff)).map(i => dateToModify.add(1,'months').format('MMMM YYYY'));

JSFIDDLE Example

Answer 2

如果您只想获取string中两个月之间的月份名称：

您首先需要声明一个array的名称，其中所有months的名称都已排序。
从您的string中提取两个月。
在几个月的indexes中获得两个months中的array。
在两个array之间遍历indexes并获得月份。

这应该是这样的代码：

var temp = "Date between March 2017 and June 2018";
var dateStrings = temp.match(/(\w+\s\d{4})/gi);

const monthNames = ["January", "February", "March", "April", "May", "June",
  "July", "August", "September", "October", "November", "December"
];
let index1 = monthNames.indexOf(dateStrings[0].split(" ")[0]);
let index2 = monthNames.indexOf(dateStrings[1].split(" ")[0]);
let year1 = dateStrings[0].split(" ")[1];
let year2 = dateStrings[1].split(" ")[1];

var diff = +year2 - +year1;
var results = [];
if (diff == 0) {
  for (var i = index1; i <= index2; i++) {
    results.push(monthNames[i] + " " + year1);
  }
} else {
  for (var i = index1; i < monthNames.length; i++) {
    results.push(monthNames[i] + " " + year1);
  }
  diff--;
  var year = +year1 + 1;
  for (var y = 0; y < diff; y++) {
    for (var i = 0; i < monthNames.length; i++) {
      results.push(monthNames[i] + " " + year);
    }
    year++;
  }
  for (var i = 0; i <= index2; i++) {
    results.push(monthNames[i] + " " + year2);
  }
}

演示：

var temp = "Date between March 2016 and June 2018";
var dateStrings = temp.match(/(\w+\s\d{4})/gi);


const monthNames = ["January", "February", "March", "April", "May", "June",
  "July", "August", "September", "October", "November", "December"
];

let index1 = monthNames.indexOf(dateStrings[0].split(" ")[0]);
let index2 = monthNames.indexOf(dateStrings[1].split(" ")[0]);

let year1 = dateStrings[0].split(" ")[1];
let year2 = dateStrings[1].split(" ")[1];

console.log(+year2 - +year1);

var diff = +year2 - +year1;
var results = [];
if (diff == 0) {
  for (var i = index1; i <= index2; i++) {
    results.push(monthNames[i] + " " + year1);
  }
} else {
  for (var i = index1; i < monthNames.length; i++) {
    results.push(monthNames[i] + " " + year1);
  }
  diff--;
  var year = +year1 + 1;
  for (var y = 0; y < diff; y++) {
    for (var i = 0; i < monthNames.length; i++) {
      results.push(monthNames[i] + " " + year);
    }
    year++;
  }
  for (var i = 0; i <= index2; i++) {
    results.push(monthNames[i] + " " + year2);
  }
}

console.log(results);

Answer 3

也许我们也需要考虑几年。 :-) https://jsfiddle.net/z07rwmnL/17/

var months = [
  "January",
  "February",
  "March",
  "April",
  "May",
  "June",
  "July",
  "August",
  "September",
  "October",
  "November",
  "December"
]

var temp = "Date between March 2018 and June 2019";
var match = temp.match(/Date between (\S+) (\d+) and (\S+) (\d+)/);

if (match) {
  var fromMonth = match[1];
  var fromYear = parseInt(match[2], 10);
  var toMonth = match[3];
  var toYear = parseInt(match[4], 10);

  if (toYear >= fromYear) {
    var fromMonthIdx = months.indexOf(fromMonth);
    var toMonthIdx = months.indexOf(toMonth);

    while (toYear >= fromYear) {
      var endIdx = (toYear > fromYear) ? 12 : toMonthIdx;
      for (var i = fromMonthIdx + 1; i < endIdx; i++) {
        console.log(months[i] + " " + fromYear);
      }
      fromMonthIdx = -1;
      fromYear++;
    }
  }
}

Answer 4

您可以简单地使用for循环在几个月之间获取距离，

var monthNames = [ "January", "February", "March", "April", "May", "June", 
                       "July", "August", "September", "October", "November", "December" ];
                       var temp="Date between March 2018 and June 2018";
var fields=temp.split(' ');
var date2=fields[fields.length-2] +" "+fields[fields.length-1];

var date1=fields[fields.length-5] +" "+fields[fields.length-4];
for(var i = new Date(date1).getMonth(); i <= new Date(date2).getMonth();i++) {
    console.log(monthNames[i])
}

Answer 5

我认为您可以使用正则表达式找到两个日期边界，然后遍历它以得到预期的输出。请注意，此解决方案适用于跨年（无异常处理，它假定您输入的字符串为恒定格式）。

var str = "Date between March 2017 and June 2018"; 
var startRE =  /between (.*) and/g;
var endRE =  /and (.*)/g;
var start = startRE.exec(str);
var end = endRE.exec(str);
var startDate = start[1]
var endDate = end[1]

var startMonth = startDate.split(' ')[0]
var startYear = startDate.split(' ')[1]

const monthNames = ["January", "February", "March", "April", "May", "June",
  "July", "August", "September", "October", "November", "December"
];

var endMonth = endDate.split(' ')[0];
var endYear = endDate.split(' ')[1];
for(var y=startYear;y<=endYear; y++){
    if(y==endYear){
        if(startYear==endYear)
          for(var m=monthNames.indexOf(startMonth);m<monthNames.indexOf(endMonth)-1;m++){
              console.log("Output:"+monthNames[m] + " " + y);
          }
        else
          for(var m=0;m<monthNames.indexOf(endMonth);m++){
              console.log("Output:"+monthNames[m] + " " + y);
          }
    }
    else{
        if(y=startYear)
        for(var m=monthNames.indexOf(startMonth);m<12;m++){
          console.log("Output:"+monthNames[m] + " " + y);
        }
        else
        {
          for(var m=0;m<12;m++){
            console.log("Output:"+monthNames[m] + " " + y);
          }
        }
    }
}

如何获取字符串中存在的两个日期之间的所有月份？

5 个答案: