Question

我在这里再次询问我对Oracle感到困惑，似乎当我在函数无法使用的情况下使用null时，我的代码如下：它在附近出错了 "CASE WHEN :idSalesman is not null then enabled = null and deleted=0 else enabled =1 and deleted =0"条件

SELECT a.id_outlet as idOutlet , a.name , a.plant as plant, a.segment, a.street1 as alamat, a.nota_retur  
 FROM (SELECT id_outlet, name, plant, segment, street1, nota_retur FROM outlet WHERE plant = :idPlant  
 AND (id_outlet || ' ' || name || ' ' || street1) like :request  
 AND enabled = 1 AND deleted = 0 and rownum = :limits ) a  
 INNER JOIN wilayah_kerja b ON b.id_salesman = nvl(:idSalesman, b.id_salesman) AND  b.id_outlet = a.id_outlet 
 AND b.enabled = 1 AND b.deleted = 0  
 GROUP BY a.id_outlet  
 UNION  
 SELECT
    A.Id_Outlet AS Idoutlet,A.Name,A.Plant AS Plant,A.Segment,A.Street1 AS Alamat,A.Nota_Retur
FROM ( SELECT Id_Outlet,Name,Plant,Segment,Street1,Nota_Retur 
        FROM Outlet
    WHERE Plant =:Idplant 
    AND (CASE WHEN :idSalesman is not null then enabled = null and deleted=0 else enabled =1 and deleted =0 )
    AND rownum >=:limits 
    AND (Id_Outlet || ' ' || Name || ' ' || Street1) LIKE :Request
    )a
 LEFT JOIN wilayah_kerja b ON b.id_outlet = a.id_outlet 
 and rownum = :limits
 AND b.enabled = 1 
 AND b.deleted = 0  
 WHERE B.Id_Outlet Is NULL Group By A.Id_Outlet Order By Name Limit 10;

我试图将联合更改为：

 SELECT a.id_outlet as idOutlet , a.name , a.plant as plant, a.segment, a.street1 as alamat, a.nota_retur  
 FROM (SELECT id_outlet, name, plant, segment, street1, nota_retur FROM outlet WHERE plant = :idPlant  
 AND (id_outlet || ' ' ||  name || ' ' || street1 ) like :request  
 AND rownum = :limits
 AND enabled = 1 AND deleted = 0 AND NVL(:idSalesman , enabled = null AND deleted = 0))a  
 LEFT JOIN wilayah_kerja b ON b.id_outlet = a.id_outlet AND b.enabled = 1 AND b.deleted = 0  
 WHERE B.Id_Outlet Is NULL Group By A.Id_Outlet Order By Name Limit 10

使用NVL2，但是它给我“ a”附近的错误

NVL(:idSalesman , enabled = null AND deleted = 0))a

Answer 1

Oracle在SQL语句中不支持单独的布尔类型。一个问题（至少）是：

> $FreeSpace = '600'
> [int]$FreeSpace -lt 5550
>> True

解决方案只是将其表达为布尔逻辑：

Missing type map configuration or unsupported mapping.

还请注意，internal class MyTypeProfile: Profile { public MyTypeProfile() { var map = CreateMap<FromType, Data.Ef.Models.ToType>(); map.ForMember(d => d.Id, s => s.Ignore()); } }不是有效的比较（除非您永远不希望某些东西评估为真）。

Oracle-在Case .... then .... Where

1 个答案: