我已经尝试过使用正则表达式路径匹配的React Router 4，但无法正常工作。我以为我可以做这样的事情：
$ charinfo 'tͭeͤxͯtͭ oͦn tͭoͦp oͦf hͪeͤrͬeͤ'
U+0074 LATIN SMALL LETTER T [Ll]
U+036D COMBINING LATIN SMALL LETTER T [Mn]
U+0065 LATIN SMALL LETTER E [Ll]
U+0364 COMBINING LATIN SMALL LETTER E [Mn]
U+0078 LATIN SMALL LETTER X [Ll]
U+036F COMBINING LATIN SMALL LETTER X [Mn]
U+0074 LATIN SMALL LETTER T [Ll]
U+036D COMBINING LATIN SMALL LETTER T [Mn]
U+0020 SPACE [Zs]
U+006F LATIN SMALL LETTER O [Ll]
U+0366 COMBINING LATIN SMALL LETTER O [Mn]
U+006E LATIN SMALL LETTER N [Ll]
U+0020 SPACE [Zs]
U+0074 LATIN SMALL LETTER T [Ll]
U+036D COMBINING LATIN SMALL LETTER T [Mn]
U+006F LATIN SMALL LETTER O [Ll]
U+0366 COMBINING LATIN SMALL LETTER O [Mn]
U+0070 LATIN SMALL LETTER P [Ll]
U+0020 SPACE [Zs]
U+006F LATIN SMALL LETTER O [Ll]
U+0366 COMBINING LATIN SMALL LETTER O [Mn]
U+0066 LATIN SMALL LETTER F [Ll]
U+0020 SPACE [Zs]
U+0068 LATIN SMALL LETTER H [Ll]
U+036A COMBINING LATIN SMALL LETTER H [Mn]
U+0065 LATIN SMALL LETTER E [Ll]
U+0364 COMBINING LATIN SMALL LETTER E [Mn]
U+0072 LATIN SMALL LETTER R [Ll]
U+036C COMBINING LATIN SMALL LETTER R [Mn]
U+0065 LATIN SMALL LETTER E [Ll]
U+0364 COMBINING LATIN SMALL LETTER E [Mn]
基本上，将默认路径<Route path='/(|blogs/:id)/' render={(props) => (<BlogCategory {...props} />)}/>与以下路径：/匹配，并使用相同的 BlogCategory 组件进行渲染，在该组件中，我将提取/blogs/:id使用:id
我已经找到了其他方法来匹配上方的2条路径，但它们不太优雅。因此，问题是，如何将同一个组件与正则表达式匹配的多个路径一起使用，其中某些路径可能具有动态参数？