Question

我正在从数据库模型Income中获取数据。看起来就是这样

@Table(name = "Income")
public class Income extends Model {

    @Column(name = "AmountDate")
    public String amountDate;

    @Column(name = "Amount")
    public Double amount;

    @Column(name = "Day")
    public int day;

    @Column(name = "Month")
    public int month;

    @Column(name = "Year")
    public int year;
}

在我的片段中，我将从数据库中获取所有收入数据。在我的BaseAdapter中，我想创建带有月份和年份的ArrayList。看起来像这样

array = [{6, 2018}, {6, 2018}, {7, 2018}, {7, 2018} {8, 2018}]

，并且我希望从该数组中删除重复的项目，因此它看起来应该像array = [{6, 2018}, {7, 2018} {8, 2018}] 然后，我将在listview和onListViewItem中显示的数组中的数据将显示选定月份的所有数据。

这是我的BaseAdapter代码

 private class IncomeArrayAdapter extends BaseAdapter {
        private LayoutInflater inflater;
        private List<Income> incomeList;
        List<Income> listOfIncomes = new ArrayList<>();

        public IncomeArrayAdapter(List<Income> incomesList) {
            inflater = LayoutInflater.from(getActivity());
            this.incomeList = incomesList;
            for (int i = 0; i < this.incomeList.size(); i++) {
                listOfIncomes.add(this.incomeList.get(i));
            }
            Set<Income> setOfIncomes = new HashSet<>(listOfIncomes);

            listOfIncomes.clear();
            listOfIncomes.addAll(setOfIncomes);

            for (int i = 0; i < listOfIncomes.size(); i++) {
                System.out.println(listOfIncomes.get(i).month + listOfIncomes.get(i).year);
            }
        }
    }

我对Java很陌生，所以我的问题是如何创建新的ArrayList并从该列表中删除重复项？

编辑：正如我建议将equals和hashCode实现到我的Income模型中一样。这两种方法的实现有些麻烦。因此，我还将编辑我的问题。

  public int hashCode() {
        return month + year;
    }

    public boolean equals(Object o) {
        boolean flag = false;
        return flag;
    }

我的equals和hashCode实施应如何显示？

Answer 1

大多数IDE都有一种自动生成哈希码和等于函数的方法。在IntelliJ IDEA中，按Alt +插入（或右键单击>生成...）

然后单击“ equals（）和hashCode（）”

或者在Eclipse中，右键单击源上的某个位置，然后选择： “源”>“生成hashCode（）和equals（）...”

无论哪种方式，它都会为您的班级产生类似以下的内容：

public class Income extends Model {

    public String amountDate;
    public Double amount;
    public int day;
    public int month;
    public int year;

    @Override
    public int hashCode() {
        final int prime = 31;
        int result = 1;
        result = prime * result + ((amount == null) ? 0 : amount.hashCode());
        result = prime * result + ((amountDate == null) ? 0 : amountDate.hashCode());
        result = prime * result + day;
        result = prime * result + month;
        result = prime * result + year;
        return result;
    }

    @Override
    public boolean equals(Object obj) {
        if (this == obj)
            return true;
        if (obj == null)
            return false;
        if (getClass() != obj.getClass())
            return false;
        Income other = (Income) obj;
        if (amount == null) {
            if (other.amount != null)
                return false;
        } else if (!amount.equals(other.amount))
            return false;
        if (amountDate == null) {
            if (other.amountDate != null)
                return false;
        } else if (!amountDate.equals(other.amountDate))
            return false;
        if (day != other.day)
            return false;
        if (month != other.month)
            return false;
        if (year != other.year)
            return false;
        return true;
    }
}

如何实现hashCode和equals方法以从ArrayList中删除重复项

1 个答案: