Question

我有一个java方法，该方法从表A（带有BLOB）读取数据，将某些数据写入表B，最后将BLOB上传到文件服务器。这是代码：

public void insertAndUploadService() throws Exception {

    List<Tiedosto> tiedostoList = new ArrayList<>();
    Integer newRow = 0;
    boolean uploaded;

    try {
        tiedostoList = tiedostoService.getAllFiles();
    } catch (Exception e) {
        e.printStackTrace();
    }

    for (Tiedosto tiedosto : tiedostoList){
        Attachment attachment = new Attachment();
        attachment.setCustomerId(tiedosto.getCustomerId());
        attachment.setSize(tiedosto.getFileSize());

        try {
            newRow = attachmentService.createNew(attachment);
            System.out.println("************ NEW ROW CREATED IN attachments ******************************");
        } catch (Exception e) {
            e.printStackTrace();
        }

        if (newRow == 1 && tiedosto.getContent() != null){
            ByteArrayInputStream byteArrayInputStream = new ByteArrayInputStream(tiedosto.getContent());
            minioFileServer.uploadFile("test", attachment.getUuid(), tiedosto.getFileName().substring(tiedosto.getFileName().lastIndexOf("/") + 1), byteArrayInputStream,
                    byteArrayInputStream.available(), tiedostoService.getMimeType(tiedosto.getContent()));
            System.out.println("********************** Generating Upload Link ************************************ "+"\n"+
                    minioFileServer.getUploadLinkForFile("test", attachment.getUuid(), tiedosto.getFileName().substring(tiedosto.getFileName().lastIndexOf("/") + 1) ));
            uploaded = minioFileServer.fileExists("test", attachment.getUuid(), tiedosto.getFileName().substring(tiedosto.getFileName().lastIndexOf("/") + 1));

            if (uploaded == true){
                System.out.println("*********** UPLOAD SUCCESSFUL ***************");
                tiedostoService.updateService(tiedosto.getCustomerId(), tiedosto.getId());
                attachmentService.update(attachment.getUuid());
            }
        }

    }
}

如果我将POST请求发送到API端点，则类似：

@POST
@Path("attachments")
public void moveToMinio() throws Exception {
    MigrationService migrationService = new MigrationService();
    migrationService.insertAndUploadService();
}

它将根据需要进行工作并打印出详细信息。发送POST请求时，是否有可能从insertAndUploadService发送多个响应？例如，当newRow创建并上传== true时，是否可以返回HTTP 202？我是Java新手，非常感谢任何帮助/建议！

编辑： “多个响应”可能不是正确的用语。我想要返回基于请求操作选择的几种HTTP状态代码之一的选项。

用Java返回多个响应

0 个答案: